[英]PHP XPath to return parent nodes based on 'child' values
Is it possible to run just a single query to replace multiple queries?是否可以只运行一个查询来替换多个查询?
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/@exclude
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/../problem[1]
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/../reference[1]
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/../impact[1]
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/../background[1]
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/../resolution[1]
For some reason this doesn't work in PHP's xpath() function.由于某种原因,这在 PHP 的 xpath() function 中不起作用。
//host_info[hostname="localhost" and vulnerability_id="remote_execution"]/(*, ../background, ../impact, ../problem)
I feel there has to be a better way here.我觉得这里必须有更好的方法。 Please note it's possible to have multiple
<host_info>
nodes which is why I'm targeting the hostname and vulnerability_id.请注意,可能有多个
<host_info>
节点,这就是我针对主机名和漏洞 ID 的原因。 But there are only one <background>
, <resolution>
nodes contained in the parent <vulnerability_id>
node.但是父
<vulnerability_id>
节点中只包含一个<background>
、 <resolution>
节点。
<report>
<vulnerability>
<host_info>
<hostname></hostname>
<vulnerability_id></vulnerability_id>
</host_info>
<host_info>
<hostname></hostname>
<vulnerability_id></vulnerability_id>
</host_info>
<background></background>
<resolution></resolution>
</vulnerability>
<vulnerability>
<host_info></host_info>
<host_info></host_info>
<host_info></host_info>
<host_info></host_info>
<background></background>
<resolution></resolution>
</vulnerability>
</report>
A node list has only a single dimension, so it is not really useful to serialize details of multiple items into a single list.节点列表只有一个维度,因此将多个项目的详细信息序列化到单个列表中并不是很有用。
Typically you would use one Xpath expression to identify your list nodes and then DOM methods and relative expressions to fetch data related to these nodes:通常,您会使用一个 Xpath 表达式来识别您的列表节点,然后使用 DOM 方法和相关表达式来获取与这些节点相关的数据:
$document = new DOMDocument();
$document->loadXML($xml);
$xpath = new DOMxpath($document);
foreach ($xpath->evaluate('//host_info[hostname="localhost" and vulnerability_id="remote_execution"]') as $hostInfo) {
var_dump(
[
$hostInfo->getAttribute('exclude'),
$xpath->evaluate('string(parent::*/background)', $hostInfo),
$xpath->evaluate('string(parent::*/resolution)', $hostInfo)
]
);
}
For a single item it is possible to fetch all the detail nodes into a single result list.对于单个项目,可以将所有详细节点提取到单个结果列表中。 However an expression like that will get complex fast and you then have to add logic that recognizes the different detail nodes.
但是,这样的表达式会很快变得复杂,然后您必须添加识别不同细节节点的逻辑。
$document = new DOMDocument();
$document->loadXML($xml);
$xpath = new DOMxpath($document);
$expression = <<<'XPATH'
//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/@exclude|
(//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/parent::*/background)[1]|
(//host_info[hostname="localhost" and vulnerability_id="remote_execution"][1]/parent::*/resolution)[1]
XPATH;
foreach ($xpath->evaluate($expression) as $detail) {
var_dump(
$detail->localName, $detail->textContent
);
}
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