将 oneline 命令放入别名中

Question

I can't put this command into a linux alias.

du --max-depth=1 | sort -nr | awk ' BEGIN { split("KB,MB,GB,TB", Units, ","); } { u = 1; while ($1 >= 1024) { $1 = $1 / 1024; u += 1 } $1 = sprintf("%.1f %s", $1, Units[u]); print $0; } '

I've tried in multiple ways but a I only get multiple syntax errors. I try to escape $ sign, put " in the begin and end but it doesn't works.

Answer 1

Do not bother with aliases. They have been effectively deprecated for over 2 decades. It is trivial to use a function. Put this in your startup scripts:

foo() { du --max-depth=1 | sort -nr | awk  ... ; }

Answer 2

As others pointed out it's much easier to use a function.

If you really want to use an alias, put the command in a file and follow these steps:

[STEP 101] # cat file
du --max-depth=1 | sort -nr | awk ' BEGIN { split("KB,MB,GB,TB", Units, ","); } { u = 1; while ($1 >= 1024) { $1 = $1 / 1024; u += 1 } $1 = sprintf("%.1f %s", $1, Units[u]); print $0; } '
[STEP 102] # eval alias foo="$( printf %q "$( < file )" )"
[STEP 103] # alias foo
alias foo='du --max-depth=1 | sort -nr | awk '\'' BEGIN { split("KB,MB,GB,TB", Units, ","); } { u = 1; while ($1 >= 1024) { $1 = $1 / 1024; u += 1 } $1 = sprintf("%.1f %s", $1, Units[u]); print $0; } '\'''
[STEP 104] #

Then copy the outputed alias definition into your bashrc or somewhere you like.