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如何在 PHP 中查找给定数字的字符串的出现字母

[英]How to find the occurrences letters of a string for given number in PHP

I have string $str = 'street';我有字符串$str = 'street'; and I want to write a function output($str, $n)我想写一个 function output($str, $n)

Here the $n is the count for number of occurrences in the given string.这里的$n是给定字符串中出现次数的计数。 I don't want to use any PHP inbuilt functions like converting it to array first or substr_count or any other for this and want to do this just with pure for looping if it is possible我不想使用任何 PHP 内置函数,例如先将其转换为数组或substr_count或任何其他函数,并且如果可能的话,只想使用纯循环来执行此操作

Considering $n as 2, the expected output is:-考虑 $n 为 2,预期的 output 是:-

t -> 2 t -> 2

e -> 2 e -> 2

$input = 'street';
$n = 2;

function outputs($input, $n)
{
    $input = str_replace(' ', '', $input);

    $characters = str_split($input);

    $outputs = [];

    foreach ($characters as $char)
    {
        if(!isset($outputs[$char])){
            $outputs[$char] = 1;
        } else {
            $outputs[$char] += 1;
        }
    }

    foreach ($outputs as $char => $number)
    {
        if ($number == $n) {
            echo $char . ' -> ' . $number;
            echo "\n";
        }
    }
}

outputs($input, $n);

So here, I have tried this above code and it works absolutely fine, but here I used the str_split function for this.所以在这里,我已经尝试了上面的代码,它工作得很好,但是在这里我使用了 str_split function 。 I want to avoid its usage and need it to be done with looping only if it's possible.我想避免使用它,并且只有在可能的情况下才需要使用循环来完成它。

I am bad at formatting questions so please spare me on this.我不擅长格式化问题,所以请原谅我。

You can use a for loop instead:您可以改用 for 循环:

<?php

$input = 'street';
$n = 2;

function outputs($input, $n)
{
    $input = str_replace(' ', '', $input);

    $outputs = [];

    for($i = 0; $i < strlen($input); $i++)
    {
        if(!isset($outputs[$input[$i]])){
            $outputs[$input[$i]] = 1;
        } else {
            $outputs[$input[$i]] += 1;
        }
    }

    foreach ($outputs as $char => $number)
    {
        if ($number == $n) {
            echo $char . ' -> ' . $number;
            echo "\n";
        }
    }
}

outputs($input, $n);

If you can't use strlen you can use while loop with isset :如果你不能使用strlen你可以使用while循环isset

$i = 0;
while(isset($input[$i])) {
    if(!isset($outputs[$input[$i]])){
        $outputs[$input[$i]] = 1;
    } else {
        $outputs[$input[$i]] += 1;
    }
    $i++;
}

Removing both the str_split and the str_replace() functions can be done by using the fact that a string can be accessed as an array, so loop over the string and pick out each character by it's position in the string...删除str_splitstr_replace()函数可以通过使用字符串可以作为数组访问的事实来完成,因此循环字符串并通过字符串中的 position 选择每个字符...

function outputs($input, $n)
{
    $outputs = [];
    for ( $i = 0; $i < strlen($input); $i++ )
    {
        $char = $input[$i];
        if ( $char != ' ' ) {
            if(!isset($outputs[$char])){
                $outputs[$char] = 1;
            } else {
                $outputs[$char] += 1;
            }
        }
    }

    foreach ($outputs as $char => $number)
    {
        if ($number == $n) {
            echo $char . ' -> ' . $number;
            echo "\n";
        }
    }
}

to remove the strlen() , just check if each element of the string is set...要删除strlen() ,只需检查是否设置了字符串的每个元素...

function outputs($input, $n)
{
    $outputs = [];
    $i = 0;
    while ( isset($input[$i]))
    {
        $char = $input[$i];
        if ( $char != ' ' ) {
            if(!isset($outputs[$char])){
                $outputs[$char] = 1;
            } else {
                $outputs[$char] += 1;
            }
        }
        $i++;
    }

    foreach ($outputs as $char => $number)
    {
        if ($number == $n) {
            echo $char . ' -> ' . $number;
            echo "\n";
        }
    }
}

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