使用正则表达式修复命名空间

Question

I have the following name spaces coming from a certain service

<soapenv:Envelope xmlns:soapenv=http://schemas.xmlsoap.org/soap/envelope/ xmlns:soap=http://www.4cgroup.co.za/soapauth xmlns:gen=http://www.4cgroup.co.za/genericsoap>

Trying to parse this request I receive the following error

xml.etree.ElementTree.ParseError: not well-formed

I noticed there is no "" on namespace value. How can I add them with regular expression

Proper format

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://www.4cgroup.co.za/soapauth" xmlns:gen="http://www.4cgroup.co.za/genericsoap">

Note double quotes

Answer 1

Using regex:

import re
namespace = "<soapenv:Envelope xmlns:soapenv=http://schemas.xmlsoap.org/soap/envelope/ xmlns:soap=http://www.4cgroup.co.za/soapauth xmlns:gen=http://www.4cgroup.co.za/genericsoap>"

FIND_URL = re.compile(r"((?:(?:https?|ftp):\/\/)?[\w/\-?=%.]+\.[\w/\-?=%.]+)")

print(FIND_URL.sub(r'"\1"', namespace))

Output:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://www.4cgroup.co.za/soapauth" xmlns:gen="http://www.4cgroup.co.za/genericsoap">

Note that the regex isn't perfect. It works for this case but if the urls become more "unique" it may fail.

Credit to this answer

Answer 2

This regex seems to do the trick:

import re
nsmap = "<soapenv:Envelope xmlns:soapenv=http://schemas.xmlsoap.org/soap/envelope/ xmlns:soap=http://www.4cgroup.co.za/soapauth xmlns:gen=http://www.4cgroup.co.za/genericsoap>"
nsmap = re.sub(r"(https?://.*?)(?=\sxmlns|>)", r'"\1"', nsmap)
print(nsmap)

Output:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://www.4cgroup.co.za/soapauth" xmlns:gen="http://www.4cgroup.co.za/genericsoap">

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