如何解决减少 java 中表达式中使用的条件运算符 (5) 的数量（最多允许 3 个）的声纳问题

Question

ObjectTest systemError = (ObjectTest ) o;
//New Code 
result &= Objects.equals(this.exp1, systemError.exp1);
result &= Objects.equals(this.exp2, systemError.exp2)  ;
result &= Objects.equals(this.exp3, systemError.exp3);
result &= Objects.equals(this.exp4, systemError.exp4);
result &= Objects.equals(this.exp5, systemError.exp5) ;
result &= Objects.equals(this.exp6, systemError.exp6);
return result;
//Old Code
return Objects.equals(this.exp, systemError.exp) &&
Objects.equals(this.exp1, systemError.exp1) &&
Objects.equals(this.exp2, systemError.exp2) &&
Objects.equals(this.exp3, systemError.exp3) &&
Objects.equals(this.exp4, systemError.exp4) &&
Objects.equals(this.exp5, systemError.exp5) &&
Objects.equals(this.exp6, systemError.exp6);

Does the New code is the solution for Old code?Can any one shed some confirmation on this.

Answer 1

Note that a &= b is same as a = a & b which will have the same result as a = a && b for practical purposes (except for performance as irrespective of the value of a , b will also be evaluated in case of a & b while in case of a && b , b is not processed if a is false )

On this basis, your new code can be indeed the solution for the old code provided you start your new code with result = Objects.equals(this.exp, systemError.exp); and end it with return result;

Feel free to let me know if you still have any problem understanding it and I will try to elaborate my explanation a bit further.