如何在 yii2 中显示来自两个不同表的数据？

Question

I am new to yii2. I have CONDITIONALLY 2 tables: Users (id, address, ...) and Profiles (id, user_id, ...).

I want to get an array of such a plan:

  {
        "ID": 2,
        "User_ID": 6,
        "Address":???
},
  {
        "ID": 3,
        "User_ID": 11,
        "Address":??
}
]

To do this, I call in the controller Profiles::getProfiles(condition);

public static function getProfiles(condition){
   return self::find->where(condition)->all();

Now I have an array of ActiveRecords objects, but without an address property. If I add the address property to them, I get an error Setting unknown property: app\models\Profiles::Address

I read about hasMany, hasOne, but I need the address property to be on par with the rest of the profile data.

Please tell me how to do it right

Answer 1

In Profile class:

use app\models\User;

//within the body of the Profile class itself
public $address;
public function getUser(){
    return $this->hasOne(User::class,[‘id’=>’User_ID’]);
}

Then you can do the following from wherever you want:

$result = Profile::find()
    ->joinWith(‘user’)
    ->select([
     ‘profile.id’, // assumes the table name is profile
    ‘user.address’, // assumes the table name is user
    ])
->where([‘profile.id’=>$value])
->all();

Answer 2

Don't make it this complicated. it's very easy in yii2, look:

Modify your Profile Model :

1 - validation rules:

public function rules() {
    return [
        [['user_id'], 'exist', 'targetClass' => User::className(), 'targetAttribute' => ['user_id' => 'id']],
    ];
}

2- getUser():

public function getUser() {
    return $this->hasOne(User::className(), ['id' => 'user_id']);
}

from now on, every instance of profile model, will have an attribute named ->user (look at the name of the method: get User () ), and it is a active record object of the User model . See, we can access address everywhere just like this:

$address = Profile::findOne($id)->user->address;