Map spring rest Z594C103F2C6E04C3D8AB059F031E0C1的路径

Question

I have a spring boot application with the following context path:

server.servlet.context-path:/api

I need to write a rest controller that's mapped to http://localhost:8080/logout instead of http://localhost:8080/api/logout

Is there a way to achieve this? changing the "server.servelt.context-path" value is not an option.

this is what I tried and didn't work:

@GetMapping(value="../signout"){
public void logout(){
}

Answer 1

Nero, you say you can't change the "server.servlet.context-path" value. I bet you say this because you don't want to break the API, but I think you can manage to change this without breaking the API. Set the context-path to blank, which is permitted. Then in your application change the "api" mapping, which I assume is currently "/", to "api".

1. Change server.servlet.context-path:/api to server.servlet.context-path:/ or maybe server.servlet.context-path: (no slash). (Supposedly this is the default so you might just remove this entry altogether.)

2. Somewhere in your application change @RequestMapping("/") to @RequestMapping("/api") .

Now you can also have @GetMapping(value="/signout") and you will have resources at http://localhost:8080/logout and http://localhost:8080/api .

I don't know what mapping annotations you happen to be using, but hopefully this is clear enough.

Answer 2

It may not be possible within that application to go outside its context root. Maybe you can create a separate Rest service app for that particular url and take it from there.