如何使随机数（低于 50 毫秒）不会重复两次

Question

I'm making script and it generates random numbers in milliseconds (Range 20-100), let's say it generated delays: 30, 40, 42 (All < (less than) 50)

Now I want to make it so 4th delay cant be again less than 50, I tried this:

I tried using for loop, but my when i use this code script doesn't work at all anymore / it won't toggle or anything.

Just imagine you made script and it generates random numbers from 20-100 and you dont want 4 in row delays that are less than 50, what would you do? Thanks.

        for (int i = 0; i < 4;)
        {

            // Total Delay aka delay1+delay2
            if (totaldelay < 50)
            {
                i++;
            }

            // Should make totaldelay > 50
            if (i == 3)
            {
                delay1 = RandomInt(75, 105);
            }

            // Reset to 0 so it checks from 0 again
            if (total > 50)
            {
                i = 0;
            }





        }

Answer 1

If I understand the question correctly, you don't want four consecutive numbers to be all less than 50. You can achieve this by simply keeping a count and adjusting your behaviour so that you generate a different number if the previous three were all less than 50.

If you're looking for a standalone C++ function to do that (give you one random number per call, with your specific added limitations), you can use something like:

int getMyRand() {
    // Keep track of how many consecutive under-50s already done.
    // Careful in multi-threaded code, may need thread-local instead.

    static int consecUnder50 = 0;
    int number;

    // If last three were all < 50, force next one to be >= 50.

    if (consecUnder50 == 3) {
        number = rand() % 51 + 50;  // 50-100 (inclusive).
    } else {
        number = rand() % 81 + 20;  // 20-100 (inclusive).
    }

    // If less, record it, otherwise restart count.

    if (number < 50) {
        ++consecUnder50;
    } else {
        consecUnder50 = 0;
    }

    // Give caller the number.

    return number;
}

---

Don't forget to seed the random number generator before using this, and be aware that C++ has better random number generators, although rand() is usually fine unless you're a statistician or cryptographer:-)