如何在 php 上的 SQL 上进行反向 LIKE？

Question

I want to select a value from a database in sql with php. So, the value that I want to select is a part of the value which I compare it with.

There are two tables: one is called event and the other weekly. In the table event, there is a column called name, that is the name of each event. Weekly has also a column called name, and it´s the name of the weekly. So, I want to get the id from a weekly comparing the two names. But the name of the event can have something before and/or after the name. For example:

Weekly name: Monday

Weekly id: 1

Event: NJK Monday 3


Another example:

Weekly name: Tuesday

Weekly id: 2

Event: Tuesday ks

I´ve tried to do it with a LIKE condition, but I didn´t earn the result that I wanted.

$stmt = $conn->prepare("UPDATE db.event SET weeklyid ="
                    . " (SELECT id FROM db.weekly WHERE %name%"
                    . " LIKE  'NJK Monday 3') WHERE name = :name;");
            $stmt->bindValue('name', $event->name);
            $stmt->execute();

So, it´s like an inverse LIKE. The result that I want to get from the code above would be that the select sentence return 1.

Answer 1

You can use CONCAT() to add the % symbols around the attribute like this

SELECT id FROM db.weekly WHERE 'NJK Monday 3' LIKE CONCAT('%', name, '%')

Answer 2

I'm not sure how it works with named placeholders by if you will use ? placeholder you should add % to execute values not to query:

wrong

$stmt = $conn->prepare('SELECT id FROM db.weekly WHERE name LIKE %?%');
$stmt->execute(['NJK Monday 3']);

good

$stmt = $conn->prepare('SELECT id FROM db.weekly WHERE name LIKE ?');
$stmt->execute(['%NJK Monday 3%']);