如何在 java 中打印两个字符串变量时删除多余的空格

Question

  public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        int T = scan.nextInt();
        for ( int i=0; i<T ; i++)
        {
            String str = scan.next();

            int even =0 , odd =0, len = str.length();
            String str1=null, str2=null;

            char [] str_even = new char[50];
            char [] str_odd = new char[50];

            for ( int j=0 ; j<len ; j ++)
            {
                if ( j %2 ==0)
                {
                    str_even[even] = str.charAt(j);
                    even++ ;
             str1 = String.valueOf(str_even);
                }

                if (j%2!=0)
                {
                    str_odd[odd] = str.charAt(j);
                    odd++ ;
                    str2 = String.valueOf(str_odd);
                }
            }
           String output = str1+str2 ;
            System.out.print(output);

        }

        scan.close();
    }

if inputstring is

Hacker
Rank

Expected output:

Hce akr
Rn ak

My Output:

Hce                          akr
                    Rn
a

Answer 1

It looks like you are converting the entire fixed length char[] into a String , but you only want the a portion of it. Fortunately there is a three-arg overload of String.valueOf that combines a substring .

str1 = String.valueOf(str_even, 0, even);

It lookes like you will also need to add a separator space back into the output.

(Not that there aren't other general issues with the code.)

Answer 2

if you want to remove spaces there are many options.

// Remove spaces , tabs and returns
System.out.println(text.replaceAll("\\s",""));

// Remove spaces in the beginning and at the end
System.out.println(text.trim());

Hope it helped.

Answer 3

First, your arrays are of the wrong size. Use this:

        char [] str_even = new char[(len+1)/2];
        char [] str_odd = new char[len/2];

second, you don't need to create str1 and str2 at each iteration. Create them after the loop.