在 Postgres 中：在多个值上使用“IS DISTINCT FROM”的最简洁方法是什么？

Question

I'm trying to find all rows that have an enum column that is either NULL or otherwise distinct from a given set of enum values. I can do it with a lot of IS DINSTINCT FROM calls, but it's really verbose and I'd rather use NOT IN() syntax, but the NULL throws that off.

Here is an example of what I want to do in SQL, from this fiddle: http://sqlfiddle.com/#!17/dfae4d/8

    CREATE TYPE mood AS ENUM ('sad', 'ok', 'happy');
    CREATE TABLE people (
        name text,
        current_mood mood,
        current_mood_as_text varchar
    );
    insert into people values('Mr Happy', 'happy', 'happy');
    insert into people values('Mr Sad', 'sad', 'sad');
    insert into people values('Mr Null', NULL, NULL);

    -- This doesn't return MrUnknown because of the NULL value:
    select * from people where current_mood NOT IN ('happy');

    -- This works great, and includes Mr Null:
    select * from people where current_mood IS DISTINCT FROM 'happy';

    -- But If I want to start comparing to multiple moods, it gets more verbose fast:
    SELECT * FROM people 
    WHERE current_mood IS DISTINCT FROM 'happy' AND
    current_mood IS DISTINCT FROM 'sad';

    -- You can't write this, but it's kinda what I want:
    -- SELECT * FROM people 
    -- WHERE current_mood IS DISTINCT FROM ('happy', 'sad');

    -- For the non enum column, I could do this to make my intention and code clear and concise
    SELECT * FROM people 
    WHERE coalesce(current_mood_as_text, '') NOT IN ('happy', 'sad');

    -- But if I write this, I get an error because '' is not a valid enum value
    -- SELECT * FROM people 
    -- WHERE coalesce(current_mood, '') NOT IN ('happy', 'sad');

Is there another way to make this sort of multiple comparison more concise?

Answer 1

The solution with coalesce() :

select * 
from people 
where coalesce(current_mood not in ('happy', 'sad'), true)

SQLFiddle.

Answer 2

Yet another way:

SELECT * FROM people 
WHERE NOT EXISTS (
  SELECT FROM (VALUES ('happy'::mood), ('sad')) v(m)
  WHERE people.current_mood = v.m
);

Answer 3

Cleanest(IMO) way is to use VALUES() inside a CTE and perform NOT EXISTS() on that table expression:

---

WITH m(m) AS ( VALUES( 'happy'::mood) )
SELECT *
FROM people p
WHERE NOT EXISTS (
        SELECT * FROM m
        WHERE m.m = p.current_mood
        );