风格拖鬼元素

Question

I am facing an issue, where I am dragging a div.

While the ghost element looks good on MacOs(yes both on Chrome and FireFox),it appears to be too transparent,in Windows (yes both on Chrome and FireFox. I tried multiple approaches but nothing seems to work. So is it possible to style the ghost element?

Also, I tried to make an image of that element on the go, and use it as ghost dragging image, but the transparency issue still remains.

Answer 1

You can do this by implementing dragging of the element yourself in JavaScript. That way, you can apply a CSS class to the element while it is being dragged, which styles it in any way you wish.

 const d = 'dragging'; const container = document.getElementById('container'); const el = document.getElementById('drag'); var cOffX = 0; var cOffY = 0; el.addEventListener('mousedown', dragStart); function dragStart(e) { e = e || window.event; e.preventDefault(); cOffX = e.clientX - el.offsetLeft; cOffY = e.clientY - el.offsetTop; document.addEventListener('mousemove', dragMove); document.addEventListener('mouseup', dragEnd); el.classList.add(d); container.style.cursor = 'move'; }; function dragMove(e) { e = e || window.event; e.preventDefault(); el.style.top = (e.clientY - cOffY).toString() + 'px'; el.style.left = (e.clientX - cOffX).toString() + 'px'; }; function dragEnd(e) { e = e || window.event; e.preventDefault(); document.removeEventListener('mousemove', dragMove); document.removeEventListener('mouseup', dragEnd); el.classList.remove(d); container.style.cursor = null; };

 #container { width: 100vw; height: 100vh; margin: 0; padding: 0; } #drag { position: absolute; height: 100px; width: 100px; background-color: lime; border-radius: 0; transition: background-color 0.25s, border-radius 0.25s; cursor: move; } #drag.dragging { background-color: navy; border-radius: 50%; }

 <div id="container"> <div id="drag"></div> </div>

As others have said, the ghosting is browser-based and can't be changed, so it seems you need your own solution if you want to get around that.