[英]Spring Google OAuth2 With Refresh Token
My current OAuth2 configuration doesn't return refresh token.我当前的 OAuth2 配置不返回刷新令牌。 My configuration is as basic as possible.
我的配置尽可能基本。 How can I configure it so that it would return refresh_token as well.
我该如何配置它,以便它也能返回 refresh_token 。 I'm authenticating user on the server side.
我正在服务器端对用户进行身份验证。 So JS solutions don't work.
所以JS解决方案不起作用。
I need the refresh token for RememberMe functionality.我需要 RememberMe 功能的刷新令牌。 Specifically I'm using
oAuth2AuthorizedClientService.loadAuthorizedClient(clientId, principalName);
具体来说,我正在使用
oAuth2AuthorizedClientService.loadAuthorizedClient(clientId, principalName);
method, to get access to the information that was retrieved from googles authentication server.方法,以访问从谷歌身份验证服务器检索到的信息。
WebSecurityConfigurerAdapter {
...
httpSecurity
...
.and()
.oauth2Login()
.and()
.rememberMe()
...
Application.yml:应用程序.yml:
security:
oauth2:
client:
registration:
google:
clientId: ZZZ
clientSecret: zzzz
redirectUri: https://example.com/login/oauth2/code/google
My solution was to add OAuth2AuthorizationRequestResolver我的解决方案是添加OAuth2AuthorizationRequestResolver
In OAuth2AuthorizationRequestResolver
I changed the customAuthorizationRequest
(see below).在
OAuth2AuthorizationRequestResolver
我更改了customAuthorizationRequest
(见下文)。 Now it returns refresh token every time.现在它每次都返回刷新令牌。
private OAuth2AuthorizationRequest customAuthorizationRequest( OAuth2AuthorizationRequest authorizationRequest) {
Map<String, Object> additionalParameters =new LinkedHashMap<>(authorizationRequest.getAdditionalParameters());
additionalParameters.put("access_type", "offline");
return OAuth2AuthorizationRequest.from(authorizationRequest)
.additionalParameters(additionalParameters)
.build();
}
also updated my WebSecurityConfigurerAdapter
还更新了我的
WebSecurityConfigurerAdapter
.oauth2Login()
.authorizationEndpoint()
.authorizationRequestResolver(
new CustomAuthorizationRequestResolver(
this.clientRegistrationRepository))
.and()
.and()
.rememberMe()
if somebody finds simpler solution do post: :)如果有人找到更简单的解决方案,请发布::)
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