取一个 integer 数组并仅打印 java 中连续 3 顺序的数字。 如果没有找到数字，则打印无

Question

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    int n,num;

    System.out.println("Enter Size: ");
    n = input.nextInt();

    int arr[] = new int [n];

    System.out.println(" Enter numbers: ");
    num = input.nextInt();


    for (int i = 0; i <=3; i++) 
    { 

        int j; 
        for (j = 0; j <= 3; j++) 
        if (arr[i] == arr[j]) 
            break; 


        if (i == j) 
        System.out.print( arr[i] + " ");
    }
}

How do I solve this?

For example:

Input: 1232221144433

Expected output: 2 4

Answer 1

Convert the input number to an integer array and then iterate over this array to find numbers occurring thrice consecutively

    private static int[] convertToArray(long input) { 
        String temp = Long.toString(input);
        int[] arr = new int[temp.length()];
        for (int i = 0; i < temp.length(); i++)
            arr[i] = temp.charAt(i) - '0';
        return arr;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter numbers: ");
        long input = scanner.nextLong();
        int[] numbers = convertToArray(input);
        for(int i = 0; i < numbers.length - 2; i ++) {      
            if(numbers[i] == numbers[i+1] && numbers[i] == numbers[i+2]) {
                System.out.println(numbers[i]);
            }
        }
        scanner.close();
    }