如何将手机设为ID Spring-boot

Question

How can I make sure that only the phone and message are sent to my database because now I also have the ID of each request that was successfully saved. I want to make the phone a unique identifier by which the values for repeats will be compared in the database.

How to make phone as ID.

UserController

@RestController
@RequestMapping("/users")
public class UserController {
    @Autowired
    private UserRepo userRepo;
    @PostMapping(consumes = {MediaType.APPLICATION_XML_VALUE, MediaType.APPLICATION_JSON_VALUE})
    public String createUser(@Valid @RequestBody User requestUserDetails) {
        userRepo.save(requestUserDetails);

        return "The message delivered.";
    }
}

User

    @Entity
@Table(name = "ApiTable", schema = "TestApi")
public class User {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;

    private String phone;

    private String message;


    public String getPhone() {
        return phone;
    }

    public void setPhone(String phone) {
        this.phone = phone;
    }

    public String getMessage() {
        return message;
    }

    public void setLastName(String message) {
        this.message = message;
    }
}

Application

@SpringBootApplication
public class Application {
    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

UserRepo

public interface UserRepo extends CrudRepository<User, Long> {

}

Answer 1

Here is how to make phone field an Id based on your example:

@Entity
@Table(name = "ApiTable", schema = "TestApi")
public class User {

    @Id   
    private String phone;

    private String message;

    public String getPhone() {
        return phone;
    }

    public void setPhone(String phone) {
        this.phone = phone;
    }

    public String getMessage() {
        return message;
    }

    public void setLastName(String message) {
        this.message = message;
    }
}

And your repository will look like:

public interface UserRepo extends CrudRepository<User, String> {
}

Answer 2

Simply use @UniqueConstraint in phone,message pair and create a new field for id.

@Entity
@Table(name = "ApiTable", schema = "TestApi",
uniqueConstraints={@UniqueConstraint(columnNames = {"phone" , "message"})
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", unique=true, nullable = false)
    private Long id;

    private String phone;

    private String message;

    public String getPhone() {
        return phone;
    }

    public void setPhone(String phone) {
        this.phone = phone;
    }

    public String getMessage() {
        return message;
    }

    public void setLastName(String message) {
        this.message = message;
    }
}

Answer 3

You didn't add what are the columns for phone and message. Try with this.

@Embeddable
public class KeyUser implements Serializable {

    @Column(name = "Phone", nullable = false)
    private int phone;

    @Column(name = "Message", nullable = false)
    private int message;

    /** getters and setters **/
}