XML 转表<for-each></for-each>

Question

I am trying to turn the following into a table, but I am having a hard time understanding how it parses through all of the child nodes.我正在尝试将以下内容转换为表格，但我很难理解它是如何解析所有子节点的。 Will it go through each element until the last one or do I need to have a for-each for each parent node?它会通过每个元素 go 直到最后一个元素，还是我需要为每个父节点设置一个 for-each ？ Also, if there are multiple occurrences of "capris" allowed, do I need to have cells for each possible occurrence (say if there are 3 max but I only have 2, then I would still need 3 cells displayed).此外，如果允许多次出现“capris”，我是否需要为每个可能出现的单元格设置单元格（例如，如果最多有 3 个但我只有 2 个，那么我仍然需要显示 3 个单元格）。

XML: XML：

<Persons xmlns = "">
<Person>
   <Shirts>One</Shirts>
   <Pants>
      <Jeans>
          <Shorts>One</Shorts>
          <Capris>One</Capris>
          <Capris>Two</Capris>
      </Jeans>
      <Dress>One</Dress>
   </Pants>
</Person>
<Person>
   <Shirts>One</Shirts>
   <Pants>
      <Jeans>
          <Shorts>One</Shorts>
          <Capris>One</Capris>
          <Capris>Two</Capris>
          <Capris>Three</Capris>
      </Jeans>
      <Dress>One</Dress>
   </Pants>
</Person>
</Persons>

XSL: XSL：

<table border="1">
   <tr bgcolor="yellow"> 
   <td><b>Shirts</b></td> 
   <td><b>Shorts</b></td> 
   <td><b>Capris</b></td>
   <td><b>Capris</b></td>
   <td><b>Capris</b></td>
</tr>
<xsl:for-each select="Persons">
  <xsl:sort select="Persons/Persib" />
    <tr style="font-size: 10pt; font-family: verdana">
    <td><xsl:value-of select="Shirts"/></td>
    <td><xsl:value-of select="Shorts"/></td>
    <td><xsl:value-of select="Capris"/></td>    
    </tr>
</xsl:for-each>
</table>

Answer 1

You had your xsl:for-each matching rule wrong.您的xsl:for-each匹配规则错误。
Use the following template: it matches the root <Persons> element, creates the <html> and <body> elements and the <table> .使用以下模板：它匹配根<Persons>元素，创建<html>和<body>元素以及<table> 。

Finally, it iterates over the <Person> elements with an xsl:for-each .最后，它使用xsl:for-each遍历<Person>元素。 This works, because the context node is right ( Person is a child of Persons ).这是可行的，因为上下文节点是正确的（ Person是Persons的子节点）。

The Capris situation is resolved by iterating over all Capris elements and creating a <td> for each present element. Capris情况通过遍历所有Capris元素并为每个当前元素创建一个<td>来解决。 You can see this by looking at the borders of the elements.您可以通过查看元素的边界来看到这一点。

One thing left to be corrected is the xsl:sort element.需要更正的一件事是xsl:sort元素。 It tries to sort by the value of a <Persib> element which is not present in the example.它尝试按示例中不存在的<Persib>元素的值进行排序。 I guess that you can fix this on your own.我想你可以自己解决这个问题。

<xsl:template match="/Persons">   
    <html>
        <body>
            <table border="1">
                <tr bgcolor="yellow"> 
                    <td><b>Shirts</b></td>
                    <td><b>Shorts</b></td>
                    <td><b>Capris</b></td>
                    <td><b>Capris</b></td>
                    <td><b>Capris</b></td>
                </tr>
                <xsl:for-each select="Person">
                    <xsl:sort select="Persib" />
                    <tr style="font-size: 10pt; font-family: verdana">
                        <td>
                            <xsl:value-of select="Shirts"/>
                        </td>
                        <td>
                            <xsl:value-of select="Pants/Jeans/Shorts"/>
                        </td>

                        <xsl:for-each select="Pants/Jeans/Capris">
                            <td>
                                <xsl:value-of select="." />
                            </td>
                        </xsl:for-each>
                    </tr>
                </xsl:for-each>
            </table>
        </body>
    </html>
</xsl:template>

The output should be as desired. output 应符合要求。

XML 转表<for-each></for-each>

问题描述

1 个解决方案

解决方案1
0 2019-11-01 05:01:36

XML 转表<for-each></for-each>

问题描述

1 个解决方案

解决方案1 0 2019-11-01 05:01:36

解决方案1
0 2019-11-01 05:01:36