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尝试使用 Java 中的递归任务(分叉和连接)计算 (3*3)^2 时出错

[英]Error when trying to calculate (3*3)^2 using Recursive Task (Fork and Join) in Java

I have to use Java Recursive Task (Fork and Join) to calculate something like this: (3*3)^2.我必须使用Java Recursive Task (Fork and Join)来计算如下内容:(3 * 3)^ 2。

I have this code which is supposed to work:我有这个应该可以工作的代码:

public class ForkJoin1 extends RecursiveTask<Long> {
    int num;
    public ForkJoin1 (int num) {
        this.num = num;
    }
    @Override
    protected Long compute() {
        if(num == 0) return Long.valueOf(1);
        ForkJoin1 fj1 = new ForkJoin1(num*num);
        ForkJoin1 fj2 = new ForkJoin1((int) Math.pow(num, 2));
        fj1.fork();
        return fj1.compute() + fj2.join();
    }
    public static void main (String[] args) {
        ForkJoinPool pool = new ForkJoinPool();
        System.out.println("Result:  " + pool.invoke(new ForkJoin1(3)));
    }    
}

However, when I run it, I get this error:但是,当我运行它时,我收到此错误: 在此处输入图像描述

What am I doing wrong?我究竟做错了什么?

Please, note that I'm new at Recursivetask in Java.请注意,我是 Java 中 Recursivetask 的新手。

Your code calls compute with num = 3 ,您的代码使用num = 3调用compute
so you create a new object and call compute with num = 9 (3 * 3) ,所以你创建一个新的 object 并使用num = 9 (3 * 3)调用compute
so you create a new object and call compute with num = 81 (9 * 9) ,所以你创建一个新的 object 并使用num = 81 (9 * 9)调用compute
so you create a new object and call compute with num = 6561 (81 * 81) ,所以你创建一个新的 object 并使用num = 6561 (81 * 81)调用compute
so you create a new object and call compute with num = 43046721 (6561 * 6561) ,所以你创建一个新的 object 并使用num = 43046721 (6561 * 6561)调用compute
so you create a new object and call compute with num = -501334399 (43046721 * 43046721) ,所以你创建一个新的 object 并使用num = -501334399 (43046721 * 43046721)调用compute
... ...

Oops, numeric overflow .糟糕,数字溢出 Well it continues anyway, with num having the following values, from the beginning:好吧,无论如何它都会继续,从一开始就num具有以下值:

3
9
81
6561
43046721
-501334399
2038349057
-1970898431
120648705
1995565057
-1876701183
-1454923775
1989099521
2099150849
977076225
1954152449
-386662399
-773324799
-1546649599
1201668097
-1891631103
511705089
1023410177
2046820353
-201326591
-402653183
-805306367
-1610612735
1073741825
-2147483647
1
1
1
1
1
...

As you can see, num never becomes 0 , so the calls never stop.如您所见, num永远不会变成0 ,因此调用永远不会停止。

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