[英]How to upload files using JDK 11 java.net.http.HttpClient?
I recently encountered some problems with java.net.http.HttpClient that comes with JDK 11. I don't know how to use file upload.最近遇到JDK 11自带的java.net.http.HttpClient的一些问题,不知道怎么用文件上传。 Found the ofInputStream() in java.net.http.BodyPublishers.
在 java.net.http.BodyPublishers 中找到了 ofInputStream()。 I don't know if I using this method file upload.
我不知道我是否使用这种方法文件上传。 Here are the examples I wrote.
以下是我写的例子。
public HttpResponse<String> post(String url, Supplier<? extends InputStream> streamSupplier, String... headers) throws IOException, InterruptedException {
HttpRequest.Builder builder = HttpRequest.newBuilder()
.uri(URI.create(url))
.headers(headers)
.POST(null == streamSupplier ?
HttpRequest.BodyPublishers.noBody() : HttpRequest.BodyPublishers.ofInputStream(streamSupplier));
HttpRequest request = builder.build();
log.debug("Execute HttpClient Method:『{}』, Url:『{}』", request.method(), request.uri().toString());
return client.send(request, HttpResponse.BodyHandlers.ofString());
}
The HttpRequest type provide factory method for creating request publisher for handling body type such as file: HttpRequest 类型提供工厂方法来创建请求发布者以处理文件等主体类型:
HttpRequest.BodyPublishers::ofFile(Path)
You can update your method:您可以更新您的方法:
public HttpResponse<String> post(String url, Path file, String... headers) throws IOException, InterruptedException {
HttpRequest request = HttpRequest.newBuilder()
.uri(URI.create(url))
.headers(headers)
.POST(null == file ? HttpRequest.BodyPublishers.noBody() :
HttpRequest.BodyPublishers.ofFile(file))
.build();
log.debug("Execute HttpClient Method:『{}』, Url:『{}』", request.method(),
request.uri().toString());
return client.send(request, HttpResponse.BodyHandlers.ofString());
}
The java.net.http.HttpClient
handles bytes supplied through the BodyPublisher
as raw body data, without any interpretation. java.net.http.HttpClient
将通过BodyPublisher
提供的字节作为原始正文数据进行处理,无需任何解释。 Whether you use HttpRequest.BodyPublishers::ofFile(Path)
or HttpRequest.BodyPublishers::ofByteArray(byte[])
is therefore semantically irrelevant: what changes is simply how the bytes that will be transmitted are obtained.因此,无论您使用
HttpRequest.BodyPublishers::ofFile(Path)
还是HttpRequest.BodyPublishers::ofByteArray(byte[])
在语义上都是无关紧要的:变化只是如何获得将要传输的字节。 In case of file upload - your server probably expects that the request body will be formatted in certain ways.在文件上传的情况下 - 您的服务器可能希望请求正文将以某些方式格式化。 It might also expect some specific headers to be transmitted with the request (such as
Content-Type
etc).它还可能期望一些特定的标头与请求一起传输(例如
Content-Type
等)。 The HttpClient
will not do that magically for you. HttpClient
不会为您神奇地做到这一点。 This is something you need to implement at the caller level.这是您需要在调用者级别实现的东西。
I tried this method, but I still found it unworkable, my God, this is too difficult, this is my demo.这个方法我试过了,还是不行,天哪,太难了,这是我的demo。
@PostMapping("/upload")
public ApiResult upload(@RequestParam("file") MultipartFile file) throws IOException, InterruptedException {
HttpResponse<String> response;
Supplier<? extends InputStream> streamSupplier = () -> {
try {
return file.getInputStream();
} catch (IOException e) {
e.printStackTrace();
}
return null;
};
response = httpClientSyncUtils.post("http://example.com/upload", streamSupplier ,
"Content-Type", "multipart/form-data");
return ApiResult.success(response.body());
}
you may use the method by:您可以通过以下方式使用该方法:
public void uploadLocalFileToRemote(String notEncodedUrlStr, String remoteFilename, String localSourceDir, String localFilename) {
Path sourcePath = Path.of(localSourceDir, localFilename);
if(!sourcePath.toFile().canRead())
{
System.err.println("please check the local file existance/readability: " + sourcePath.toAbsolutePath());
return;
}
FileInputStream ins = null;
try {
ins = new FileInputStream(sourcePath.toFile());//FileNotFoundException extends IOException
BufferedInputStream buf_ins = new BufferedInputStream(ins);
Supplier<? extends InputStream> streamSupplier = new Supplier<BufferedInputStream>() {
@Override
public BufferedInputStream get() {
return buf_ins;
}
};
//HttpResponse<String> response = post(notEncodedUrlStr, streamSupplier,
HttpResponse<String> response = post(notEncodedUrlStr, () -> buf_ins,
"User-Agent", "Java 11 HttpClient Bot", "Content-type", "application/octet-stream",
"accept", "*/*", "fileName", remoteFilename);
// print response:
System.out.println(response.version().name() + " " + response.statusCode());
// print response headers
HttpHeaders headers = response.headers();
headers.map().forEach((k, v) -> System.out.println(k + ":" + v));
// print response body
String body = response.body();
System.out.println(body);
} catch (IOException | InterruptedException e) {
e.printStackTrace();
}
}
another consideration is how your server side is implemented.另一个考虑因素是您的服务器端是如何实现的。 here assume the server side will using http 1.1 "chunked".
这里假设服务器端将使用 http 1.1 “分块”。 and configured a directory for remoteFilename.
并为 remoteFilename 配置了一个目录。
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