python 中的新行列表

Question

How can I create a list that starts in a new line because right now my menu looks like this:

Choose index in [(0, 'Display ID'), (1, 'Display Balance'), (2, 'Display Annual Interest Rate'), (3, 'Display Monthly Interest Rate'), (4, 'Display Monthly Interest'), (5, 'Withdraw Money'), (6, 'Deposit Money'), (7, 'Exit')]

and I need it to look like this:

Choose index in (0) Display ID

(1) Display Balance

(2) Display Annual Interest Rate

(3) Display Monthly Interest Rate

(4) Display Monthly Interest

(5) Withdraw Money

(6) Deposit Money

(7) Exit

I have tried using '\n'.join but it doesn't work.

 actions = ["Display ID",
               "Display Balance",
               "Display Annual Interest Rate",
               "Display Monthly Interest Rate",
               "Display Monthly Interest",
               "Withdraw Money",
               "Deposit Money",
               "Exit"]
        while True:
            choice = int(input("Choose index in " + str(list(enumerate(actions)))))
            apply_actions(choice, acc)

Answer 1

Instead of:

choice = int(input("Choose index in " + str(list(enumerate(actions)))))

Do:

print("Choose index in ")
for i, action in enumerate(actions):
    print("(" + str(i) + ") " + action)

Alternatively:

print("Choose index in \n" + "\n".join(["(" + str(i+1) + ") " + action for i, action in enumerate(actions)]))