如何按列表的长度重复列表中的最大元素

Question

Write a Python function called all_change_to_max_end that takes as input a list of integers, determines which is larger, the first or last element in the list, and then sets all the other elements to be that value. Output the changed list.

Sample inputs and output:

all_change_to_max_end([1, 2, 4, 9, 3]) # should be [3, 3, 3, 3, 3] 

all_change_to_max_end([11, 5, 9])      # should be [11, 11, 11] 

all_change_to_max_end([2, 11])         # should be [11, 11]

I've tried using:

def all_change_to_max_end(a_list):

    return max(a_list) * len(a_list)

but this does not work as it multiples the largest number by the total length

all_change_to_max_end([2, 10, 4, 8]

40

Any help would be greatly appreciated!

Answer 1

You need to check the max of these two elements (first and last)

def all_change_to_max_end(a_list):
    return [max(a_list[0], a_list[-1])] * len(a_list)

Answer 2

The correct answer is: [max(a_list[-1], a_list[0])] * len(a_list) .

Answer 3

Pass a list in this function:

def all_change_to_max_end(x):
    #select maximum and converting it to list
    return [max(x[0], x[-1])]*(len(x)) 

numbers = [1, 5, 8, 4, 3, 7, 9, 7]

print(all_change_to_max_end(numbers))

Out[79]: [7, 7, 7, 7, 7, 7, 7, 7]

Answer 4

Do this change

When you do max(list) it returns a value not a list so multiplying it to a number is simple multiplication.

max(list) * len(list) #let max = 10 and length = 4, then its output is 40

so do

[max(list[0],list[-1])] 

This is sample output

>>> a = [1, 2, 4, 9, 3]
>>> def all_change_to_max_end(a_list):
...     return [max(a_list[0],a_list[-1])] * len(a_list)
...
>>> all_change_to_max_end(a)
[3, 3, 3, 3, 3]

Answer 5

you can do:

def all_change_to_max_end(l):
    a = l[0]
    b = l[-1]
    return [max(a,b)] * len(l)

print(all_change_to_max_end([11, 5, 9]))

output

[11, 11, 11]