[英]How can I access a specific value from the dictionary returned by this object in Python
I have an object that returns the following list:我有一个返回以下列表的 object:
[[0, 'virtual_94',
{'sequence': 10,
'display_type': False,
'product_uom_qty': 1,
'qty_delivered_manual': 0,
'price_unit': 1000,
'discount': 0,
'customer_lead': 0,
'product_id': 1,
'product_no_variant_attribute_value_ids': [[6, False, []]],
'name': 'Produto de teste',
'product_uom': 1,
'analytic_tag_ids': [[6, False, []]],
'route_id': False,
*'tax_id': [[6, False, [**1**]]],*
'sale_line_exemption_id': False}]]
How can I access a specific value on this list?如何访问此列表中的特定值? In my case, I need to access the value "1" that can be found on
'tax_id': [[6, False, [**1**]]]
就我而言,我需要访问可以在
'tax_id': [[6, False, [**1**]]]
Like this.像这样。
infos = [[0, 'virtual_94', {'sequence': 10, 'display_type': False, 'product_uom_qty': 1, 'qty_delivered_manual': 0, 'price_unit': 1000, 'discount': 0, 'customer_lead': 0, 'product_id': 1, 'product_no_variant_attribute_value_ids': [[6, False, []]], 'name': 'Produto de teste', 'product_uom': 1, 'analytic_tag_ids': [[6, False, []]], 'route_id': False, 'tax_id': [[6, False, [1]]], 'sale_line_exemption_id': False}]]
ID = infos[0][2]["tax_id"][0][2][0]
You can access lists with their respective indexes and dictionary values with their respective keys.您可以使用它们各自的索引访问列表,并使用它们各自的键访问字典值。
Here's a breakdown to get to your desired output:这是获得所需 output 的细分:
#Access the third element (index 2) in your initial list to get a dictionary
d = your_list[2]
#Get value for key 'tax_id' : [[6, False, [**1**]]]
tax_id_list = d['tax_id']
# Get sublist: [6, False, [**1**]]
tax_id_sub_list = tax_id_list[0]
# Get list with one in it: [**1**]
element_with_one = tax_id_sub_list[2]
#Finally, access the first element in that list: 1
print(element_with_one[0])
Outputs:输出:
1
Merging all the above into a single line (however, harder to read):将以上所有内容合并到一行中(但是,更难阅读):
print(your_list[0][2]['tax_id'][0][2][0])
Outputs:输出:
1
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