如何直接从命令行登录应用程序，即在 Pytest 的命令行中提供 URL、用户名、密码

Question

Instead of hard coding the URL of the application under test in the code, I would like to pass it as an argument in the command line. Also, the username, password.

Currently I get below error

ERROR: file not found:

pytest -v -s --html=.\Reports\report.html test_practise.py https://testurl

Below is my Login function:

class LoginPage():

    def __init__(self, driver):
        self.driver = driver
        self.url = 'https://test-url'


def go(self):
    self.driver.get(self.url)    


def enter_username(self,text):
    username_xpath = "//input[@id='emailOrUsername']"
    WebDriverWait(self.driver, 20).until(EC.element_to_be_clickable((By.XPATH, username_xpath))).send_keys(text)


def enter_password(self,text):    
    password_xpath = "//input[@id='pass']"
    WebDriverWait(self.driver, 20).until(EC.element_to_be_clickable((By.XPATH, password_xpath))).send_keys(text)


def click_login_button(self):    
    login_btn_xpath = "//span[contains(text(),'Login')]"
    self.driver.find_element_by_xpath(login_btn_xpath).click()

def get_login_btn_text(self):
    login_btn_xpath = "//span[contains(text(),'Login')]"
    login_btn_text = self.driver.find_element_by_xpath(login_btn_xpath).text
    return login_btn_text

Answer 1

There is a built-in module argparse . Check the tutorial by the link .

import argparse
parser = argparse.ArgumentParser()
parser.add_argument("echo")
args = parser.parse_args()
print(args.echo)

And here is a result: $ python3 prog.py --help usage: prog.py [-h] echo

positional arguments:
  echo

optional arguments:
  -h, --help  show this help message and exit
$ python3 prog.py foo
foo