解析 Python 中的列表

Question

I am trying sentiment analysis with MONKEYLEARN API in python.

When I print the result I get the following response.

[{'text': 'Today is a very good weather', 'external_id': None,'error': False, 'classifications': [{'tag_name': 'Positive', 'tag_id':60333048, 'confidence': 0.987}]}]

The result if of type list and I want to isolate only the classification results from this list that is the

TAG_NAME: Positive and the Confidence: 0.987

Answer 1

All the answers worked efficietly. I went with answer by AVION and Sayandip Dutta.

classification_result = lst[0]['classifications'][0]
tag_name = classification_result['tag_name']
confidence = classification_result['confidence']

Answer 2

Say you are getting the response like this:

lst = [{'text': 'Today is a very good weather', 'external_id': None, 'error': False, 'classifications': [{'tag_name': 'Positive', 'tag_id': 60333048, 'confidence': 0.987}]}]

Do this:

classification_result = lst[0]['classifications'][0]
tag_name = classification_result['tag_name']
confidence = classification_result['confidence']

Answer 3

    result = [{'text': 'Today is a very good weather', 'external_id': None, 'error': False, 'classifications': [{'tag_name': 'Positive', 'tag_id': 60333048, 'confidence': 0.987}]}]
    classification_result = result[0].get("classifications")[0]

Now this is dictionary from which following can get gathered:

• tag_name using classification_result["tag_name"]
• tag_id using classification_result["tag_id"]
• confidence using classification_result["confidence"]

it is nested dictionary inside list, and list inside dictionary

Answer 4

Filter looks right choice here if rs is your result you can also wrap it in a function to avoid harcoding tag_name and confidence values

rs = [{'text': 'Today is a very good weather', 'external_id': None, 'error': False, 'classifications': [{'tag_name': 'Positive', 'tag_id': 60333048, 'confidence': 0.987}]}]

filtered_result =  filter(lambda record: record['classifications'][:1].get("tag_name")== 'Positive' and record['classifications'][:1].get('confidence') == 0.987,rs)

list(filtered_result)

Answer 5

Just get the element you from the list and then select classification . You can easily this if you print your list.

your_list = [{'text': 'Today is a very good weather', 'external_id': None,'error': False, 'classifications': [{'tag_name': 'Positive', 'tag_id':60333048, 'confidence': 0.987}]}]
print(your_list)
#output
[{'text': 'Today is a very good weather',
  'external_id': None,
  'error': False,
  'classifications': [{'tag_name': 'Positive',
    'tag_id': 60333048,
    'confidence': 0.987}]}]

Then do this

your_list[0]['classifications']