[英]How to create unpaged but sorted Pageable.of(unpaged, unpaged, Sort ) to spring data jpa repository?
How do I pass a Pageable
object to Spring JPA Repository with only Sorting information?如何将可分页 object 传递给Pageable
JPA 存储库,仅包含排序信息? I want something like this:我想要这样的东西:
Pageable pageable = PageRequest.of(null, null, Sort());
I know it takes int
as page
and size
but if we can somehow not use those values and give an unpaged result with only我知道它需要int
作为page
和size
,但是如果我们不能以某种方式不使用这些值并仅给出未分页的结果
Sort.by(Sort.Direction.ASC, "age")
We could use a high number like 1000
, 1000
for page and size but I do not want to hardcode these values.我们可以使用像1000
、 1000
这样的大数字来表示页面和大小,但我不想硬编码这些值。
I am also not looking to create a custom impl for Pageable
.我也不打算为Pageable
创建自定义 impl。
Please let me know how to achieve this.请让我知道如何实现这一目标。
Thanks in advance.提前致谢。
According to the documentation for the current version of Spring Data JPA , you can pass a Sort
directly to a query method, so you could have two versions of the same query method:根据Spring 数据 JPA 当前版本的文档,您可以将Sort
直接传递给查询方法,因此您可以有两个版本的相同查询方法:
Pageable
, for use when you have a "full" Pageable
.一个接收Pageable
,当你有一个“完整的” Pageable
时使用。Sort
, for use when you just want to perform sorting.另一个接收Sort
,当您只想执行排序时使用。 You could pass Pageable.unpaged()
in the query and then sort the result ( list.getContent().sort(Comparator.comparing(Item::getName))
) if you are adamant about using the existing query.如果您坚持使用现有查询,则可以在查询中传递Pageable.unpaged()
然后对结果进行排序( list.getContent().sort(Comparator.comparing(Item::getName))
)。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.