如何在 Oracle SQL 中仅使用数字字符的 select 行

Question

I would like to keep rows only with Numeric Character ie 0-9. My source data can have any type of character eg 2,%,(.

Input (postcode)
3453gds sdg3
454232
sdg(*d^
452

Expected Output (postcode)
454232
452

I have tried using WHERE REGEXP_LIKE(postcode, '^[[:digit:]]+$'); however in my version of Oracle I get an error saying

function regexp_like(character varying, "unknown") does not exist

Answer 1

For Oracle 10 or higher you can use regexp functions. In earlier versions translate function will help you:

SELECT  postcode
FROM    table_name
WHERE   length(translate(postcode,'0123456789','1')) is null
AND     postcode IS NOT NULL;

OR

SELECT translate(postcode, '0123456789' || translate(postcode,'x123456789','x'),'0123456789') nums
   FROM table_name  ;

the above answer also works for me

SELECT translate('1234bsdfs3@23##PU', '0123456789' || translate('1234bsdfs3@23##PU','x123456789','x'),'0123456789') nums
   FROM dual  ;

Nums:
1234323

Answer 2

You want regexp_like() and your version should work:

select t.*
from t
where regexp_like(t.postcode, '^[0-9]+$');

However, your error looks more like a Postgres error, so perhaps this will work:

t.postcode ~ '^[0-9]+$'

Answer 3

For an alternative to the Gordon Linoff answer, we can try using REGEXP_REPLACE :

SELECT *
FROM yourTable
WHERE REGEXP_REPLACE(postcode, '[0-9]+', '') IS NULL;

The idea here is to strip away all digit characters, and then assert that nothing were left behind. For a mixed digit-letter value, the regex replacement would result in a non-empty string.