统计SQL中多个表的过滤数据

Question

I have 2 tables config_location_workstation and asset_workstation where both have the columns floor and workstation_number.

I want a query to return something like this:

FLOOR| SUM PRODUCTION WORKSTATION | SUM HEAD COUNT

This code below came from another source which I was able to pull up the sum but the numbers are incorrect because what I want to get is the number of all Production workstation.

SELECT config_location_workstation1.floor,
       (SELECT COUNT(config_location_workstation2.workstation_number)
        FROM config_location_workstation AS config_location_workstation2
        WHERE config_location_workstation2.floor = config_location_workstation1.floor) AS SUM_FLOOR,
       (SELECT COUNT(asset_workstation2.workstation_number)
        FROM asset_workstation AS asset_workstation2
        WHERE asset_workstation2.floor = config_location_workstation1.floor) AS SUM_HEAD
FROM config_location_workstation AS config_location_workstation1
INNER JOIN asset_workstation AS asset_workstation1
    ON (config_location_workstation1.workstation_number = asset_workstation1.workstation_number)
WHERE config_location_workstation1.workstation_name = 'NORTH PRODUCTION'
GROUP BY config_location_workstation1.floor

The problem is WHERE is not working on this code. The Workstation Column sum is invalid. It is pulling up all the entries. I only need to query all PRODUCTION workstations

Here's the current output.

+-------+-------------+------+------+
| Floor | Head Count  | Workstations|
+-------+-------------+------+------+
| 18TH  | 696         | 576         |
| 19TH  | 381         | 463         |
| 20TH  | 380         | 760         |
+-------+-------------+------+------+

Expected output for all Production workstations

+-------+-------------+------+------+
| Floor | Head Count  | Workstations|
+-------+-------------+------+------+
| 18TH  | 696         | 497         |
| 19TH  | 381         | 388         |
| 20TH  | 380         | 659         |
+-------+-------------+------+------+

Answer 1

Probably you could try using a subquery

select * from (
SELECT config_location_workstation1.floor,config_location_workstation1.workstation_name as z,
       (SELECT COUNT(config_location_workstation2.workstation_number)
        FROM config_location_workstation AS config_location_workstation2
        WHERE config_location_workstation2.floor = config_location_workstation1.floor) AS SUM_FLOOR,
       (SELECT COUNT(asset_workstation2.workstation_number)
        FROM asset_workstation AS asset_workstation2
        WHERE asset_workstation2.floor = config_location_workstation1.floor) AS SUM_HEAD
FROM config_location_workstation AS config_location_workstation1
INNER JOIN asset_workstation AS asset_workstation1
    ON (config_location_workstation1.workstation_number = asset_workstation1.workstation_number)
GROUP BY config_location_workstation1.floor
) x
WHERE z = 'NORTH PRODUCTION'

UPDATE:

select x.*,y.* from ( SELECT *, COUNT(workstation_name) as COUNT_FLOOR 
FROM config_location_workstation WHERE workstation_name LIKE '%PRODUCTION%' GROUP BY floor)x 
join 
(SELECT *, COUNT(floor) as COUNT_USERS FROM asset_workstation GROUP BY floor) y on 
x.workstation_number = y.workstation_number