如何编写 python 正则表达式来查找两个用斜线分隔的电话号码？

Question

I have want to extract the phone number using regex. i have phone series like 0097444603826,96824437746 and 0030693221591 / 0030693221550

my regex pattern = [-()\s\d]+?(?=\s*[+<]) everthing extracting but in last number 0030693221591 / 0030693221550 it is taking only second 0030693221550 i want help in writing regex like it should extract 0030693221591 / 0030693221550

Answer 1

import re

def main():
    data = 'i have phone series like 0097444603826,96824437746 and 0030693221591 / 0030693221550'
    match = re.findall('(\\d+\\s?[,/]\\s?\\d+)', data)
    for i in match:
        print(i)

if __name__ == '__main__':
    main()

() is a capture group (which is around the whole expression)

\d+ 1 or more 0-9

\s? 0 or 1 whitespace

[,/] either , or /

This returns:

0097444603826,96824437746
0030693221591 / 0030693221550