[英]How to select a value based on a column value?
Suppose, Member table has a column named Contact假设, Member表有一个名为Contact的列
If Contact has value, Then Type = 1 Otherwise, Type will be blank如果 Contact 有值,则 Type = 1 否则,Type 将为空
What will be the SQL to retrieve Contact and Type检索联系人和类型的 SQL 将是什么
You can use case statement
:您可以使用
case statement
:
SELECT contact, CASE WHEN contact IS NOT NULL THEN 1 AS type
FROM membertable
You can use IIF()
function which is introduced and supported after SQL Server 2012.您可以使用在 SQL Server 2012 之后引入和支持的
IIF()
function。
Syntax:句法:
IIF (boolean_expression, true_value, false_value)
IIF (boolean_expression, true_value, false_value)
Use:利用:
SELECT concat, IIF(COALESCE(contact, '') != '', '1', '') AS [type]
FROM Member
Just use a case in your query to generate the type column.只需在查询中使用一个案例来生成类型列。
SELECT
contact,
CASE
WHEN contact IS NOT NULL then 1
ELSE ''
END as type
FROM Member
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