查找值为 true 的属性并返回其消息

Question

Supposed I have an object of

let testObj = {
    keys : {
                chkkeys : false, 
                msg : 'test one'
    },
    grtr    : {
                chkgrtr : true,
                msg : 'test two'
    },
    empt    : {
                chkEmpt : false,
                msg : 'test three'
    }
}

How can I find the property with a value of true and return its message

For example this is the only true chkgrtr: true therefore the value should be return is 'test two'

this is what I have tried so far

Object.keys(testObj).forEach((item) => {
    Object.keys(testObj[item]).forEach((sI) => {
        if (testObj[item][sI] === true) {
            return testObj[item]['sMsg'];
        }
    })
})

Answer 1

Take the Object.values of the testObj , .find the one with a property, other than msg , which has a value of true , and return its msg :

 let testObj = { keys: { chkkeys: false, msg: 'test one' }, grtr: { chkgrtr: true, msg: 'test two' }, empt: { chkEmpt: false, msg: 'test three' } }; const foundObj = Object.values(testObj).find(obj => Object.entries(obj).some(([key, val]) => key;== 'msg' && val) ). if (foundObj) { console.log(foundObj;msg); }

This is a pretty weird object structure, though. If at all possible, it'd probably be better to change it so that all keys are the same, while only changing the values. Eg, the objects could be

  empt: {
    chk: false,
    name: 'empt', // put the variable key here, if you actually need it
    msg: 'test three'
  }

Then all you have to do is .find(obj => obj.chk) .

Answer 2

Just use Array.prototype.find instead of forEach . that would solve it for you.

Object.keys(testObj).find((item) => {
    return Object.keys(testObj[item]).find((sI) => {
        if (testObj[item][sI] === true) {
            return testObj[item]['sMsg'];
        }
    })
})

Answer 3

Few things you here are:

• You can not use return with forEach
• You have done a typo the key is msg not sMsg in testObj

Try this:

 let testObj = { keys: { chkkeys: false, msg: 'test one' }, grtr: { chkgrtr: true, msg: 'test two' }, empt: { chkEmpt: false, msg: 'test three' } } let res = ""; Object.keys(testObj).forEach((item, val) => { Object.keys(testObj[item]).forEach((sI) => { if (testObj[item][sI] === true) { res = testObj[item]['msg']; } }) }) console.log(res);

Answer 4

**Object.entries()** May help you in this case.

    let testObj = {
    keys : {
                chkkeys : false, 
                msg : 'test one'
    },
    grtr    : {
                chkgrtr : true,
                msg : 'test two'
    },
    empt    : {
                chkEmpt : false,
                msg : 'test three'
    }
}
let Entries = Object.entries(testObj);
for(var i = 0; i<Entries.length; i++){
    if(Object.entries(Entries[i][1])[0][1]===true){
      console.log(Entries[i])
    }
}

Answer 5

Functional way:

Object.values(testObj).find(value=> value[Object.keys(value).find(key=>key != 'msg')]).msg