“rpm -qf”的等价物是什么<FILE> &quot; 使用 Python rpm 库？

Question

# rpm -qf /usr/lib64/python3.7/site-packages/six.py
python3-six-1.12.0-r0

How do I use Python to query which package the file belongs to?

Answer 1

I was going to say Google it, but it actually doesn't return results. I guess it's a very unorthodox way of approaching the problem/asking the question.

Python default uses pip to install packages. Find the documentation here

Another option is easy_install , and many recommend doing it through conda which requires Anaconda and requires more set-up but manages a nice controlled Python environment to manage versions within.

Google should show you those.

Answer 2

I've not found a direct call to the rpm database that gives in return the package providing a given file, so the better solution I've right now is the following:

#!/usr/bin/env python3

import rpm

CHECK_FILE = "/usr/lib/python3.9/site-packages/six.py"

ts = rpm.TransactionSet()
mi = ts.dbMatch()
for h in mi:
    files = h['FILENAMES']
    if CHECK_FILE in files:
        print("{}-{}-{}".format(h['name'], h['version'], h['release']))
        break