如何修复代码以打开代码块中命令提示符中传递的文件

Question

I'm trying to pass the names of the arguments to be readen in codeblocks through set program arguments. When I open them directly, I use

    FILE * file_1 = fopen("file31.ll", "r");
    FILE * file_2 = fopen("file32.ll", "r");

And it works, cause file31 and file32 are in the same paste as the file. However, when I create a project (and put the files inside its paste), I try to write file31.ll and file32.ll in the arguments and it doesn't work. When compilling, the program warns that the files couldn't be open because the directory wasn't found ("error opening the file: no such a file or directory"). I've also tried writing "file31" and "file32", and also copied the address in Windows like: C:\Users...\opening_files\file31 where opening_files is the name of the project

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "LCS.h"

int main(int argc, char * argv[])
{
    if (argc < 3) {
        printf("Incorret number of arguments!\n");
        exit(1);
    }
    //I print argc and argv to test if the arguments are being passed correctly
    printf("argc = %d\n", argc);
    for (int i=1; i<argc; i++) {
        fputs(argv[i], stdout);
        printf("\n");
    }
    //They are printed correctly
    //However, when trying to open the files, the program warns that the
    //directories weren't found
    //Opening the files
    FILE * file_1 = fopen(argv[2], "r");
    FILE * file_2 = fopen(argv[3], "r");
    if (file_1 == NULL || file_2 == NULL)
    {
        perror("Error opening file\n");
    }

I tried to read some other posts about this online but I haven't understand them very well, cause I'm pretty new to programming.

Answer 1

The indexing of the argv[] is incorrect. The argv[1] store the file_1 path and the argv[2] store the file_2 path.

FILE * file_1 = fopen(argv[1], "r");
FILE * file_2 = fopen(argv[2], "r");