在不使用内置 python 函数的情况下替换字符串中的短语？

Question

I'm trying to write a function to replace phrases that I have stored in a list with acronyms which are also stored in a list. Trying to do this without most built in functions. Here's my best attempt thus far:

    def replace_phrase(string):
        result = ''
        for i in range(len(string)):
            counter = 0
            for phrase in phrases_to_replace_list:
                if len(phrase) < len(string[i:]):
                    pass
                elif string[i:i + len(phrase)] == phrase:
                    pre = string[:i]
                    post = string[i + len(phrase):]
                    result += pre + replacement_phrases[counter] + post
                counter += 1
        return result

With a string of "Oh my god I love you got to go" an output of "OMG ILY GTG" is what I'm trying to achieve, but the code is outputting "Oh my god I love you GTG" .

Answer 1

However In your post there is no Logic for space between OMG and ILY and GTG .

So just assume that there may group of three char.

You may try below code:

def replace_phrase(string):
  result =''
  flag=True
  cnt=3
  for c in string.strip():
    if c==' ':
      flag=True
      continue
    if flag==True:
      cnt+=1
      result=result+c.upper()
      if cnt%3==0:
        result=result+' '
      flag=False     
  return result

print(replace_phrase('Oh my god I love you got to go'))

Output:

OMG ILY GTG