比较不同List python中两个元组的项

Question

Hello freinds i need your help. I want to compare between two lists of tuples,if there is more than one identical value between the two tuples I print this result exp:

L1 = [('G', 'T'), ('T', 'T'), ('T', 'U'), ('U', 'I'), ('I', 'P')]
L2 = [('E', 'G'), ('G', 'T'), ('T', 'P')]

output: [0,1]

Answer 1

Use list comprehension:

L1 = [('G', 'T'), ('T', 'T'), ('T', 'U'), ('U', 'I'), ('I', 'P')]
L2 = [('E', 'G'), ('G', 'T'), ('T', 'P')]

indices = [[L1.index(s),i] for i, s in enumerate(L2) if s in L1]

# print the first match (in this case there is only one match)
print(indices[0])
[0, 1]

---

Explanation of [[L1.index(s),i] for i, s in enumerate(L2) if s in L1] :

• for i, s in enumerate(L2) : i is the index, s in the tuple element of L2
• if s in L1 : this checks if the current s is also in L1
• [L1.index(s),i] : this returns a list of the index

PS: For duplicates this may not behave well.

Answer 2

Here is a little more dynamic of a solution. I altered your input a little to get a different test case. This will work for duplicates and also works in O(N) time.

from collections import defaultdict
L1 = [('G', 'T'), ('T', 'T'), ('T', 'U'), ('U', 'I'), ('I', 'P'), ('U', 'I')]
L2 = [('E', 'G'), ('G', 'T'), ('T', 'P'), ('U', 'I')]
S1 = defaultdict(list)
S2 = defaultdict(list)
for indx, element in enumerate(L1):
    S1[element].append(indx)
for indx, element in enumerate(L2):
    S2[element].append(indx)

duplicate_elements = set(S1).intersection(set(S2))
print("Mutual elements:", *[(S1[dup], S2[dup]) for dup in duplicate_elements])

Output:

Mutual elements: ([0], [1]) ([3, 5], [3])