从 object 中删除虚假值，但不删除 0

Question

Is there a nicer way (for example with filter ) to remove values from object than this?

const filters = {
   a: null,
   b: 0,
   c: 'xxx',
   d: 'abc',
}

const MY_FALSY = [undefined, '', null];
const newFilters = Object.entries(filters).reduce(
  (a, [k, v]) =>
    MY_FALSY.indexOf(v) > -1 ? a : { ...a, [k]: v },
  {}
);

Is there a better way to do it? I tried to use filter but I had to use delete which as I know we should avoid.

NOTE: I don't want to use any libraries like underscore.js

Outcome:

{
   b: 0,
   c: 'xxx',
   d: 'abc',
}

Answer 1

Simply add a special case for 0 :

v || v === 0 // v must be kept
!v && v !== 0 // v must be removed

And unless there is a specific reason, you can use the delete operator:

 const filters = { a: null, b: 0, c: "", d: "keeper" } Object.keys(filters).forEach(function(k) { if (;filters[k] && filters[k];== 0) { delete filters[k]. } }); console.log(filters);

Answer 2

const removeFalsy = (myObject)=>{
  const new_obj = {...myObject};
  Object.keys(new_obj).forEach(key=> new_obj[key] || new_obj[key]===0 ? new_obj[key] : delete new_obj[key]);
  return new_obj;
}

See if this works. Here we created a pure function to copy the object, remove falsy keys and then return the new object.