试图找到这种特殊情况的正则表达式？ 我也可以在不创建组的情况下解析它吗？

Question

text to capture looks like this..

  Policy Number    ABCD000012345    other text follows in same line....

My regex looks like this

 regex value='(?i)(?:[P|p]olicy\s[N|n]o[|:|;|,][\n\r\s\t]*[\na-z\sA-Z:,;\r\d\t]*[S|s]e\s*[H|h]abla\s*[^\n]*[\n\s\r\t]*|(?i)[P|p]olicy[\s\n\t\r]*[N|n]umber[\s\n\r\t]*)(?P<policy_number>[^\n]*)'

this particular case matches with the second or case.. however it is also capturing everything after the policy number. What can be the stopping condition for it to just grab the number. I know something is wrong but can't find a way out.

 (?i)[P|p]olicy[\s\n\t\r]*[N|n]umber[\s\n\r\t]*)

current output

    ABCD000012345othertextfollowsinsameline....

expected output

   ABCD000012345

Answer 1

You may use a more simple regex, just finding from the beginning "[P|p]olicy\s*[N|n]umber\s*\b([AZ]{4}\d+)\b.*" and use the word boundary \b

pattern = re.compile(r"[P|p]olicy\s*[N|n]umber\s*\b([A-Z0-9]+)\b.*")
line = "Policy Number    ABCD000012345    other text follows in same line...."
matches = pattern.match(line)
id_res = matches.group(1)
print(id_res)  # ABCD000012345

And if there's always 2 words before you can use (?:\w+\s+){2}\b([A-Z0-9]+)\b.*

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Also \s is for [\r\n\t\f\v ] so no need to repeat them, your [\n\r\s\t] is just \s

Answer 2

you don't need the upper and lower case p and n specified since you're already specifying case insensitive.

Also \s already covers \n , \t and \r .

(?i)policy\s+number\s+([A-Z]{4}\d+)\b

for verification purpose: Regex

Another Solution:

^[\s\w]+\b([A-Z]{4}\d+)\b

for verification purpose: Regex

I like this better, in case your text changes from policy number