将字符串转换为 unicode 转义序列

Question

I would like to convert a string to a unicode escape sequence, in python 3, that I can use later. For example:

string = "Hello, World!\n"
print(string.unicode_escape())
# shoud print \u0048\u0065\u006C\u006C\u006F\u002C\u0020...

Note the function should return a raw string or escape the backslashes (so I can actauly see the escape). I have seen this post but it is not really related as it goes it over haskell.

Answer 1

The ord() function returns the Unicode code point of a character. Just format this as \\u\u003c/code> followed by a 4-digit hex representation of that.

def unicode_escape(s):
    return "".join(map(lambda c: rf"\u{ord(c):04x}", s))
print(unicode_escape("Hello, World!\n"))
# prints \u0048\u0065\u006c\u006c\u006f\u002c\u0020\u0057\u006f\u0072\u006c\u0064\u0021\u000a

Answer 2

def encode(s): ret = [] for c in s: n = ord(c) ret.append("\\u{:04x}".format(n)) return "".join(ret) # print(encode("aeiouäöüßéá€æÆΑαΒβΓγ"))