删除字符串 pandas 中的括号区域

Question

I am trying this:

There are also several countries with numbers and/or parenthesis in their name. Be sure to remove these,

eg

'Cuba (Island of Caribeas)' should be 'Cuba',

DataFrame in

    Country                         Energy    
18  Mexico                          321000000   
19  Cuba (Island of Caribeas)      102000000    
20  Algeria                        1959000000   
21  American                        2252661245  
22  Andorra(no mentioned)            9000000    

I would like to get this df (DF out)

   Country                           Energy    
18  Mexico                          321000000   
19  Cuba                           102000000    
20  Algeria                        1959000000   
21  American                        2252661245  
22  Andorra                         9000000

I am trying this

for item in df['Country']: #remove the () with the data inside
   re.sub(r" ?\(\w+\)", "", item)

But I dont get any changes in my DF, and no error, so I dont know what I am doing wrong. Please someone could help me?

Answer 1

This could be a start... try:

df['Country'] = df['Country'].apply(lambda x: re.sub(r" ?\(\w+\)", "", x))

This will apply your expression to each value in df['Country']...

Answer 2

The regular expression isn't quite right - what if there are white spaces in the brackets?

import pandas as pd

s = pd.Series(['Cuba (Island of Caribeas)', 'Andorra(no mentioned)', 'Algeria'])

s.replace(r" ?\((?:\w+ ?)+\)", "", regex=True)  

This will return:

Out[13]: 
0       Cuba
1    Andorra
2    Algeria
dtype: object

To adapt it to your example:

df['Country'] = df['Country'].replace(r" ?\((?:\w+ ?)+\)", "", regex=True)