Bash 脚本 shell：如何将文件名对应的变量用于嵌套 for 循环

Question

I have a large number of directories with their names as:

Cl_GG_Omega_m_step_1e-01_der_15
Cl_GG_Omega_m_step_2e-01_der_15
Cl_GG_Omega_m_step_2e-01_der_15
Cl_GG_Omega_m_step_1e-08_der_15
Cl_LL_Omega_m_step_1e-08_der_15
Cl_GL_Omega_m_step_1e-08_der_15
Cl_GG_Omega_m_step_1.1229481712787273e-08_der_15
Cl_LL_Omega_m_step_1.1229481712787273e-08_der_15
Cl_GL_Omega_m_step_1.1229481712787273e-08_der_15
Cl_GG_Omega_m_step_1.2610125953782405e-08_der_15
Cl_LL_Omega_m_step_1.2610125953782405e-08_der_15

I would like to get the directory name (full) whose value appearing between Òmega_m_step and _der_15 is below a cutoff (for example cutoff=0.01 below):

For this, I tried to do:

for i in $(ls --color=never -d Cl_*Omega_m_step_*); do
    for j in $(echo $i); do
        sed 's/.*_step_\([0-9].[0-9]*\)_der_15/\1/g' "$j" | awk -v cutoff=0.01 '{if ($1 < cutoff) print "$j"}'; 
    done;
done

The difficulty here is that I would like to get the entire directory name, that's why I used a double for loop: the issue is that I don't know to get into nested loop the $j directory name (coming from for j in $(echo $i) , especially printing it from awk -v cutoff=0.01 '{if ($1 < cutoff) print "$j"}' command?

Update

Thanks for your answers, it helped me a lot. Just a last thing, for the fun, how can I use with Shell bash (I mean that I make reference) the outer index $i into nested loop of a double loop, ie:

for i in $(...); do for j in $(...); do "reference to i"; done; done

Can I do a simple $i or "$i" ? You will tell me of course that it will depend on the command that uses this index in nested loop. So, even a simple case would be enough for me.

Answer 1

As noted by the comments, the file name can be broken into '_' separated tokens, including the step attribute (6th column). Awk can be used to apply a numeric filter.

ls Cl_*Omega_m_step_* | awk -F_ '$6<0.01'

Per OP question, clarification for awk programs: the following are equivalent.

condition 
condition { print }
{ if ( condition ) print }

For this example:

awk -F_ '$6<0.01'
awk -F_ '$6<0.01 { print }'
awk -F_ '{ if ($6<0.01) print }'