如何将帖子数据数组插入数据库

Question

I have a list of items was gotten from my database, then I'm using array to post the data through a from in order to insert them to my database since they are more than one.

<form method="post" actioin="courses.php">
<table>
   <thead>
     <tr>
       <th>S/N</th>
       <th>Action</th>
       <th>Course Title</th>
       <th>Course Code</th>
       <th>Course Unit</th>
     </tr>
   </thead>
   <tbody>
        <?php 
            $stmt = "SELECT * FROM courses WHERE level ='$regl'AND semester='$regsem'";
            $runStmt = $db->query($stmt);
            $counter = 0;
            while($show = $runStmt->fetch_array(MYSQLI_ASSOC))
                {
                    $id=$show['course_id'];
                    $ctitle=$show['course_title'];
                    $ccode=$show['course_code'];
                    $cunit=$show['course_unit'];?>                              
                <tr>
                   <td><?php echo ++$counter?></td>
                   <td>
                      <input type="checkbox" value="<?php echo $id?>" name="isChecked['course_id']">
                   </td>
                   <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_title']"><?php echo $ctitle?>
                    </td>
                    <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_code']"> <?php echo $ccode?>
                     </td>
                      <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_unit']">
                      <?php echo $cunit?>
                      </td>
                  </tr>
          <?php }?>
             </tbody>
       </table>
<input type ="submit" value="enroll" name="enroll">
</form>

If a checkbox is checked, How can I get all the values of the array (title, code, unit) and insert them on its corresponding column in my enroll table also note that the courses are more than 1?

so i have something on ground but it's way out of line.. so your corrections/suggestions will do:

<?php 
  if(isset($_POST['enroll'])){
  $i=0;
  if(!empty ($_POST['isChecked'])){

    $stmt = $db->prepare("INSERT INTO courses (course_id, course_title, course_code, course_unit,
    dept,level,session) 
    VALUES (?, ?, ?,?,?,?,?)");
    $stmt->bind_param("ississs", $cid, $ctitle, $ccode,$cunit,$dpt,$lvl,$sessn);

    foreach($_POST['isChecked'] as $course){  
    $course = $_POST['isChecked'][$i];
    $ctitle = $_POST['isChecked'][$i];
    $ccode = $_POST['isChecked'][$i];
    $cunit = $_POST['isChecked'][$i];
    $dpt = $stud_dept;
    $lvl = $regl;
    $sessn = $regs;
    $stmt->execute();
    $i++;

        }

      }

    }
?>

Answer 1

You can use javascript for it, just change the first row like this:

<form method="post" actioin="courses.php" onChange="this.form.submit()" >

of to compline with the critics put it at the checkbox

<form method="post" actioin="courses.php">
<table>
   <thead>
     <tr>
       <th>S/N</th>
       <th>Action</th>
       <th>Course Title</th>
       <th>Course Code</th>
       <th>Course Unit</th>
     </tr>
   </thead>
   <tbody>
        <?php 
            $stmt = "SELECT * FROM courses WHERE level ='$regl'AND semester='$regsem'";
            $runStmt = $db->query($stmt);
            $counter = 0;
            while($show = $runStmt->fetch_array(MYSQLI_ASSOC))
                {
                    $id=$show['course_id'];
                    $ctitle=$show['course_title'];
                    $ccode=$show['course_code'];
                    $cunit=$show['course_unit'];?>                              
                <tr>
                   <td><?php echo ++$counter?></td>
                   <td>
                      <input type="checkbox" value="<?php echo $id?>" name="isChecked['course_id']" onChange="this.form.submit()">
                   </td>
                   <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_title']"><?php echo $ctitle?>
                    </td>
                    <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_code']"> <?php echo $ccode?>
                     </td>
                      <td><input type="hidden" value="<?php echo $ctitle?>" name="isChecked['course_unit']">
                      <?php echo $cunit?>
                      </td>
                  </tr>
          <?php }?>
             </tbody>
       </table>
<input type ="submit" value="enroll" name="enroll">
</form>



<?php 
  if(isset($_POST['enroll'])){
  $i=0;
  if(!empty ($_POST['isChecked'])){

    $stmt = $db->prepare("INSERT INTO courses (course_id, course_title, course_code, course_unit,
    dept,level,session) 
    VALUES (?, ?, ?,?,?,?,?)");
    $stmt->bind_param("ississs", $cid, $ctitle, $ccode,$cunit,$dpt,$lvl,$sessn);

// here is your mistake you assign $_POST['isChecked'] as $course,
// then you have to use $course
//
// the next failure is you fetched the data with MYSQLI_ASSOC
// then you must call them by name like course['course_id'];
//
// what you receive is a variable called like :
// $_POST['isChecked']['course_unit']['$i']
// so you will have in your foreach $course['course_unit']['$i']
// 
    foreach($_POST['isChecked'] as $course){  
      $cid =    $course['course_id']['$i'];
      $ctitle = $course['course_title']['$i'];
      $ccode =  $course['course_code']['$i'];
      $cunit =  $course['course_unit']['$i'];
      $dpt =    $stud_dept;
      $lvl =    $regl;
      $sessn =  $regs;
    $stmt->execute();
    $i++;

        }

      }

    }
?>