我如何 select 数组中的多个值？

Question

int[] numbers = new int[] 
{ 
    1, 2, 33, 44, 55, 68, 77, 96, 100 
};

if (numbers[] % 2 == 0)
{
    Console.WriteLine("EVEN");
}

I want to make the code say even when the value in the array is an even number. How could I do this?

Answer 1

Your question is vague one:

...the code say even when the value in the array is an even number

You may want to query numbers (with a help of Linq ):

If array contains at least one even value:

 using System.Linq;

 ...

 if (numbers.Any(item => item % 2 == 0))
   Console.WriteLine("EVEN");

If array values are all even:

 if (numbers.All(item => item % 2 == 0))
   Console.WriteLine("EVEN");

Obtain even values (let's have an int[] even array):

 int[] even = numbers
   .Where(item => item % 2 == 0)
   .ToArray();

 if (even.Length > 0) 
   Console.WriteLine($"EVEN: {string.Join(", ", even)}");  

Finally, you may want to scan the numbers array and do something on each even item:

  foreach (int item in numbers) {
    if (item % 2 == 0) {
      Console.WriteLine("EVEN:");  
    } 
  }

Answer 2

You need loop

for (int i = 0; i < numbers.Length; i++)
{
  if (numbers[i] % 2 == 0)
  {
    Console.WriteLine("EVEN");
  }
}

Answer 3

I would do it:

var evenNumbers = numbers.Where(x => x % 2 == 0).ToArray();