如何将列表或数组添加到json正文中[保持]

Question

i have to use a webservice, to create user on a portal system. In my case I have a documentation how to provide the correct data for the restApi.

here is the documented how to:

Body:

{ 
   "Titel":"false",
   "Dts":[ 
      { 
         "code":"4712",
         "date":"2018-05-01"
      }
   ],
   "Info":"Here we are"
}

I tried it with restSharp, but without success. Here is my coding.

   create_user user_value = new create_user();
   add_user_dts dts_value = new add_user_dts();

   create_user.Titel = "false";
   dts_value.code = "4712";
   dts_value.date = "2018-05-01";
   create_user.DTS = dts_value;
   dts_value.Info = "Here we are";

   request.AddJsonBody(JsonConvert.SerializeObject(create_user));

But if I ask for the response, i'll get a "Bad Request"! I Checkt the serialized Object and found the problem.

{\\"Titel\\":\\"false\\",\\"DTS\\":{\\"code\\":\\"4712\\",\\"date\\":\\"2018-05-01\\"},\\"Info\\":\\"Here we are\\"}

There are missing square brackets!!
{\\"Titel\\":\\"false\\",\\"DTS\\": [ {\\"code\\":\\"4712\\",\\"date\\":\\"2018-05-01\\"} ] ,\\"Info\\":\\"Here we are\\"}

zwo can say me, how to get such brackets? Or how to fill a class or a array/list to serialize in the correct form?

I'm bloody new in json programming and in RestSharp.

who can help me? regards from Germany
-=stony007_de=-

Answer 1

In the RestRequest you can set the property JsonSerializer where its possible to define the DateFormatHandling.

I strongly recommend that you use Newtonsoft.Json for serialization.

public static RestRequest Create(Uri resource)
    {
        return new RestRequest(resource) { JsonSerializer = MyJsonSerializer.Default, RequestFormat = DataFormat.Json };
    }

In the JsonSerializer.Default you have your default date format. Something like:

public static MyJsonSerializer Default { get { return new MyJsonSerializer(new Newtonsoft.Json.JsonSerializer() { DateFormatHandling = DateFormatHandling.MicrosoftDateFormat }); } }

In MyJsonSerializer class you should define methods to serialize and deserialize objects. This process will use the format that you define.

public T Deserialize<T>(IRestResponse response)
    {
        var content = response.Content;

        using (var stringReader = new StringReader(content))
        {
            using (var jsonTextReader = new JsonTextReader(stringReader))
            {
                try
                {
                    return Serializer.Deserialize<T>(jsonTextReader);
                }
                catch (Exception exc) when (exc is JsonSerializationException || exc is JsonReaderException)
                {
                    var exception = JsonConvert.DeserializeObject<RestExceptionDetails>(response.Content);
                    throw new RestException(exception.Message, exception.ServerStackTrace);
                }
            }
        }
    }

    public string Serialize(object obj)
    {
        using (var stringWriter = new StringWriter())
        {
            using (var jsonTextWriter = new JsonTextWriter(stringWriter))
            {
                Serializer.Serialize(jsonTextWriter, obj);
                return stringWriter.ToString();
            }
        }
    }