[英]Conditionally replace column names in a dataframe based on values in another dataframe
I have downloaded a table of stream diversion data ("df_download").我已经下载了一个流转移数据表(“df_download”)。 The column names of this table are primarily taken from the ID numbers of the gauging stations.
该表的列名主要取自测站的 ID 号。
I want to conditionally replace the ID numbers that have been used for column names with text for the station names , which will help make the data more readable when I'm sharing the results.我想有条件地将用于列名的 ID 号替换为站名的文本,这将有助于在我共享结果时使数据更具可读性。 I created a table ("stationIDs") with the ID numbers and station names to use as a reference for changing the column names of "df_download".
我创建了一个包含 ID 号和站名的表(“stationIDs”),用作更改“df_download”列名的参考。
I can replace the column names individually, but I want to write a loop of some kind that will address all of the columns of "df_download" and change the names of the columns referenced in the dataframe "stationIDs".我可以单独替换列名,但我想编写某种循环来处理“df_download”的所有列并更改数据帧“stationIDs”中引用的列的名称。
An example of what I'm trying to do is below.我正在尝试做的一个例子如下。
Downloaded Data ("df_download")下载的数据(“df_download”)
A portion of the downloaded data is similar to this:部分下载的数据类似于:
df_downloaded <- data.frame(Var1 = seq(as.Date("2012-01-01"),as.Date("2012-12-01"), by="month"),
Var2 = sample(50:150,12, replace =TRUE),
Var3 = sample(10:100,12, replace =TRUE),
Var4 = sample(15:45,12, replace =TRUE),
Var5 = sample(50:200,12, replace =TRUE),
Var6 = sample(15:100,12, replace =TRUE),
Var7 = c(rep(0,3),rep(13,6),rep(0,3)),
Var8 = rep(5,12))
colnames(df_downloaded) <- c("Diversion.Date","360410059","360410060",
"360410209","361000655","361000656","Irrigation","Seep")
df_download # not run
#
# Diversion.Date 360410059 360410060 360410209 361000655 361000656 Irrigation Seep
# 1 2012-01-01 93 57 28 101 16 0 5
# 2 2012-02-01 102 68 19 124 98 0 5
# 3 2012-03-01 124 93 36 109 56 0 5
# 4 2012-04-01 94 96 23 54 87 13 5
# 5 2012-05-01 83 70 43 119 15 13 5
# 6 2012-06-01 78 63 45 195 15 13 5
# 7 2012-07-01 86 77 20 130 63 13 5
# 8 2012-08-01 118 29 27 118 57 13 5
# 9 2012-09-01 142 18 45 116 27 13 5
# 10 2012-10-01 74 68 34 182 79 0 5
# 11 2012-11-01 106 48 27 95 74 0 5
# 12 2012-12-01 91 41 20 179 55 0 5
Reference Table ("stationIDs")参考表(“stationIDs”)
stationIDs <- data.frame(ID = c("360410059", "360410060", "360410209", "361000655", "361000656"),
Names = c("RimView", "IPCO", "WMA.Ditch", "RV.Bypass", "LowerFalls"))
stationIDs # not run
#
# ID Names
# 1 360410059 RimView
# 2 360410060 IPCO
# 3 360410209 WMA.Ditch
# 4 361000655 RV.Bypass
# 5 361000656 LowerFalls
I can replace the column names in "df_downloaded" using individual statements.我可以使用单独的语句替换“df_downloaded”中的列名。 I show the first three iterations below.
我在下面展示了前三个迭代。
After three iterations "RimValley", "IPCO", and "WMA.Ditch" have replaced their respective gauge ID numbers.经过三次迭代,“RimValley”、“IPCO”和“WMA.Ditch”已经替换了各自的仪表 ID 号。
names(df_downloaded) <- gsub(stationIDs$ID[1],stationIDs$Name[1],names(df_downloaded))
# head(df_downloaded)
# Diversion.Date RimView 360410060 360410209 361000655 361000656 Irrigation Seep
# 1 2012-01-01 93 57 28 101 16 0 5
# 2 2012-02-01 102 68 19 124 98 0 5
# 3 2012-03-01 124 93 36 109 56 0 5
# 4 2012-04-01 94 96 23 54 87 13 5
# 5 2012-05-01 83 70 43 119 15 13 5
# 6 2012-06-01 78 63 45 195 15 13 5
names(df_downloaded) <- gsub(stationIDs$ID[2],stationIDs$Name[2],names(df_downloaded))
# head(df_downloaded)
# Diversion.Date RimView IPCO 360410209 361000655 361000656 Irrigation Seep
# 1 2012-01-01 93 57 28 101 16 0 5
# 2 2012-02-01 102 68 19 124 98 0 5
# 3 2012-03-01 124 93 36 109 56 0 5
# 4 2012-04-01 94 96 23 54 87 13 5
# 5 2012-05-01 83 70 43 119 15 13 5
# 6 2012-06-01 78 63 45 195 15 13 5
names(df_downloaded) <- gsub(stationIDs$ID[3],stationIDs$Name[3],names(df_downloaded))
# head(df_downloaded)
# Diversion.Date RimView IPCO WMA.Ditch 361000655 361000656 Irrigation Seep
# 1 2012-01-01 93 57 28 101 16 0 5
# 2 2012-02-01 102 68 19 124 98 0 5
# 3 2012-03-01 124 93 36 109 56 0 5
# 4 2012-04-01 94 96 23 54 87 13 5
# 5 2012-05-01 83 70 43 119 15 13 5
# 6 2012-06-01 78 63 45 195 15 13 5
If I try to do the renaming using a for
loop, I end up with NAs for column names.如果我尝试使用
for
循环进行重命名,我最终会使用 NA 作为列名。
for(i in seq_along(names(df_downloaded))){
names(df_downloaded) <- gsub(stationIDs$ID[i],stationIDs$Name[i],names(df_downloaded))
}
# head(df_downloaded)
# NA NA NA NA NA NA NA NA
# 1 2012-01-01 93 57 28 101 16 0 5
# 2 2012-02-01 102 68 19 124 98 0 5
# 3 2012-03-01 124 93 36 109 56 0 5
# 4 2012-04-01 94 96 23 54 87 13 5
# 5 2012-05-01 83 70 43 119 15 13 5
# 6 2012-06-01 78 63 45 195 15 13 5
I really want to be able to change the names with a for
loop or something similar, because because the number of stations that I download data from changes depending on the years that I am analyzing.我真的希望能够使用
for
循环或类似的东西更改名称,因为我下载数据的站点数量会根据我分析的年份而变化。
Thanks for taking time to look at my question.感谢您花时间看我的问题。
We can use match
我们可以使用
match
#Convert factor columns to character
stationIDs[] <- lapply(stationIDs, as.character)
#Match names of df_downloaded with stationIDs$ID
inds <- match(names(df_downloaded), stationIDs$ID)
#Replace the matched name with corresponding Names from stationIDs
names(df_downloaded)[which(!is.na(inds))] <- stationIDs$Names[inds[!is.na(inds)]]
df_downloaded
# Diversion.Date RimView IPCO WMA.Ditch RV.Bypass LowerFalls Irrigation Seep
#1 2012-01-01 142 14 41 200 79 0 5
#2 2012-02-01 97 100 35 176 22 0 5
#3 2012-03-01 85 59 26 88 71 0 5
#4 2012-04-01 68 49 34 63 15 13 5
#5 2012-05-01 62 58 44 87 16 13 5
#6 2012-06-01 70 59 33 145 87 13 5
#7 2012-07-01 112 65 25 52 64 13 5
#8 2012-08-01 75 12 27 103 19 13 5
#9 2012-09-01 73 65 36 172 68 13 5
#10 2012-10-01 87 35 27 146 42 0 5
#11 2012-11-01 122 17 33 183 32 0 5
#12 2012-12-01 108 65 15 120 99 0 5
You can do this dplyr and tidyr.您可以执行此 dplyr 和 tidyr。 You basically want to make your data long so that the IDs are in a column so that you can do a join on this with your reference of IDs to names.
您基本上希望使您的数据很长,以便 ID 位于一列中,以便您可以使用 ID 对名称的引用对此进行连接。 Then you can make your data wide again.
然后,您可以再次使数据变宽。
df_downloaded %>%
gather(ID, value, -Diversion.Date, -Irrigation, -Seep) %>%
left_join(., stationIDs) %>%
dplyr::select(-ID) %>%
spread(Names, value)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.