[英]Finding total number of lists and elements from a text file with list of lists structure and empty lists
I am trying to compute the total number of lists and total number of elements of a text file.我正在尝试计算文本文件的列表总数和元素总数。 The text file
try1.txt
consists of a list of lists structure like this:文本文件
try1.txt
包含一个列表结构列表,如下所示:
[[], ['i', 'am', 'a', 'good', 'boy'], ['i', 'am', 'an', 'engineer']]
import ast
global inputList
inputList = []
path = "C:/Users/hp/Desktop/folder/"
def read_data():
for file in ['try1.txt']:
with open(path + file, 'r', encoding = 'utf-8') as infile:
inputList.extend(ast.literal_eval(*infile.readlines()))
print(len(inputList))
print(sum(len(x) for x in inputList))
read_data()
The output for the above mentioned input list should be: 3 and 9.上述输入列表的输出应为:3 和 9。
I have tried but I am getting error when there is a empty list.我已经尝试过,但是当列表为空时出现错误。 Is there any way to solve the issue?
有没有办法解决这个问题? If not then I want to display the output by removing the empty lists;
如果没有,那么我想通过删除空列表来显示输出; in that case the output should be 2 and 9.
在这种情况下,输出应该是 2 和 9。
If I remove the empty list, then I am getting the output as 2 and 9. But the inclusion of empty list creating problem.如果我删除空列表,那么我得到的输出为 2 和 9。但是包含创建问题的空列表。 The error I am getting:
我得到的错误:
ValueError: malformed node or string: <_ast.Subscript object at 0x0000020E99CC0088>
This problem was not the empty list!这个问题不是空列表! It's the LF at the end of the string.
它是字符串末尾的 LF。
This code work on python 3.6:此代码适用于 python 3.6:
import ast
v = ast.literal_eval("[[],['i', 'am', 'a', 'good', 'boy'],['i', 'am', 'an', 'engineer']]")`
If the error persists on a older version and python upgrade is not a option, just remove the empty list before evaluate the expression:如果错误在旧版本上仍然存在并且 python upgrade 不是一个选项,只需在评估表达式之前删除空列表:
exp = infile.read()
empty_count = exp.count('[]')
exp = exp.replace('[],','')
inputList.extend(ast.literal_eval(*exp))
print('List Count:%d' % len(inputList)+empty_count)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.