[英]Error: expected primary-expression before ']' token in C++
I'm trying to create something similar to string.find
with vectors c++98
, but I can't fix this error.我正在尝试使用向量c++98
创建类似于string.find
的内容,但我无法修复此错误。 I have simplified the code and left only the error.我已经简化了代码,只留下了错误。 If I can get help on how to achieve this.如果我能就如何实现这一目标获得帮助。
#include <iostream>
#define MAX 99999
using namespace std;
int free_pos (int v[]);
int find_line (int v[], int pos);
int main() {
char text[MAX];
int loc_key[MAX],start_line[MAX]; //
for(int i=0; i<free_pos(loc_key);i++) {
cout << "Line: " << i+1;
int pos = find_line(start_line[],loc_key[i]); //Here is the error
for(int j=start_line[pos];j<start_line[pos+1];j++) {
cout<<text[j];
}
cout<<endl;
}
return 0;
}
int free_pos (int v[]) {
for(int i=0;i<MAX;i++){
if(v[i] == 0)
return i;
}
return 99;
}
int find_line (int v[], int pos) {
for(int i=0; i<free_pos(v); i++) {
if(v[i]==pos)
return v[i];
if(v[i]< pos)
return v[i-1];
}
}
Your both functions你的两个功能
int free_pos (int v[]);
int find_line (int v[], int pos);
take arrays as an input, but then you try to call int pos = find_line(start_line[],loc_key[i]);
将数组作为输入,然后尝试调用int pos = find_line(start_line[],loc_key[i]);
, which should take the name of an array only , as it is the name which is known by the program as an array. ,它应该只采用数组的名称,因为它是程序称为数组的名称。 You can easier (in my opinion) get it, if you write both of these functions following way:如果您按照以下方式编写这两个函数,您可以更容易(在我看来)得到它:
int free_pos (int* v);
int find_line (int* v, int pos);
They do the same job as your functions, but you can see that their arguments are: an int pointer (array) and an int.它们与您的函数执行相同的工作,但您可以看到它们的参数是:一个 int 指针(数组)和一个 int。 Then, calling the function needs only the int pointer, which in your case is start_line
, and the integer loc_key[i]
.然后,调用该函数只需要 int 指针(在您的情况下是start_line
)和整数loc_key[i]
。 If you still have problems understanding it, you could read about dynamic memory allocation of arrays, which is done as: int* arr; arr = new int[your_size];
如果你在理解它时仍然有问题,你可以阅读数组的动态内存分配,它是这样完成的: int* arr; arr = new int[your_size];
int* arr; arr = new int[your_size];
- I think it is clearer while thinking that way. - 这样想就更清楚了。
#include<bits/stdc++.h>
using namespace std;
int max(int arr[],int n){
maximum=INT_MAX;
for(int i=0;i<n;i++){
if(arr[i]>maximum){
maximum=arr[i]}}
return maximum;}
int main(){
int size;
cin>>size;
for(int i=0;i<size;i++){
cin>>arr[i]}
cout<<max(arr,size);
return 0;}
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