[英]I'm confused about the output
#include <stdio.h>
#include <stdlib.h>
int main()
{
int a , b ,c ;
printf("Enter values for a and b: ");
scanf("%d%d",&a,&b);
a = a + b-- ;
if (a<b){
c = -1;
printf("\n\t%d %d %d\n\n",a,b,c);
}
else {
c = 0;
printf("\n\t%d %d %d\n\n",a,b,c);
}
}
Lets assume the value of the input for a and b are 2 (for both of them).让我们假设 a 和 b 的输入值为 2(对于它们两者)。
I studied the above program, but when it comes to the output it will be 4 1 0, a=4,b=1,c=0.我研究了上面的程序,但是当涉及到输出时,它将是 4 1 0, a=4,b=1,c=0。 But, the calculation part above said that a=a+b-1 which will be the value of a is 3, now the new value of a is 3. But for b the value is still 2 because we didn't assign a new value to it.
但是,上面的计算部分说 a=a+b-1 这将是 a 的值是 3,现在 a 的新值是 3。但是对于 b,值仍然是 2,因为我们没有分配一个新的对它的价值。
I am very confused about the output.我对输出感到非常困惑。
There is a difference between a+1
, a++
and ++a
. a+1
、 a++
和++a
之间存在差异。 Details here .详情请看这里。 Therefore, when you say
因此,当你说
a = a + b--;
You are actually saying你实际上是在说
a = a + b;
b = b - 1;
If you say如果你说
a = a + --b;
It becomes它成为了
b = b - 1;
a = a + b;
And if you say如果你说
a = a + (b-1)
It does what you think: a = a + b - 1
.它按照您的想法执行:
a = a + b - 1
。 The value of b
doesn't change afterwards. b
的值之后不会改变。
At the beginning, a and b are both 2一开始,a和b都是2
Then, you execute a = a + b--;
然后,你执行
a = a + b--;
. .
The decrement operator is located after the b
, so it evaluates to:递减运算符位于
b
,因此其计算结果为:
a=a+b;
b=b-1;
After this, a will be 4 and b will be 1.在此之后,a 将为 4,b 将为 1。
a is not smaller than b, so c will be 0. a 不小于 b,所以 c 将为 0。
Note:笔记:
If it would be a = a + --b
, it would evaluate to如果它是
a = a + --b
,它将评估为
b=b-1;
a=a+b;
Because the --
is executed at the beginning of the evaluation.因为
--
是在评估开始时执行的。
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