按升序输出整数时将最后一个整数放在新行上

Question

In the code below, I am trying to output the integers in ascending order. It works, however I want the final integer to be put on a newline (final integer only- not the other integers). I have tried

cout << myVec[i] << " "; endl

and...

cout << myVec[i] << endl;

but, both do not give the output I am looking for (these affect the other integers which is not what I want.

#include <iostream>
#include <vector>

using namespace std;

void SortVector(vector<int>& myVec)
{
  int n = myVec.size();
  int i, j;
  for (i = 0; i < n - 1; i++)
    for (j = 0; j < n - i - 1; j++)
      if (myVec[j] > myVec[j + 1])
      {
        int temp = myVec[j];
        myVec[j] = myVec[j + 1];
        myVec[j + 1] = temp;
      }
}

int main()
{
  int i, n, value;
  cin >> n;
  vector<int> myVec;

  for (i = 0; i < n; i++)
  {
    cin >> value;
    myVec.push_back(value);
  }
  SortVector(myVec);
  for (i = 0; i < n; i++)
    cout << myVec[i] << " ";
  return 0;
}

Answer 1

Print all but the last element on one line:

for (i = 0; i < n-1; i++) // notice n-1
    std::cout << myVec[i] << ' ';
std::cout << '\n';

Then you can print the last afterwards:

if(myVec.size())
    std::cout << myVec.back() << '\n';