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如何每天只显示一次弹出窗口 vue

[英]How to display a popup only once per day vue

I have a method that shows a modal window 4 seconds after the user logs on to the site.我有一种方法可以在用户登录网站 4 秒后显示一个模态窗口。 If it is closed then show again next 24 hours.如果它已关闭,则在接下来的 24 小时内再次显示。 I have some problems.我有一些问题。 LocalStorage does not store my data and does not return a variable that stores the date, how can I fix it? LocalStorage 不存储我的数据,也不返回存储日期的变量,我该如何解决?

mounted () {
    this.runModalTimer()
    this.setDevHoursModal()
  },
  methods: {
    runModalTimer (): void {
      setTimeout(() => {
        this.isModalVisible = true
      }, 4000)
    },
    setDevHoursModal (): boolean {
      if (localStorage) {
        let nextPopup = localStorage.getItem('isModalVisible')

        if (nextPopup > new Date()) {
          return this.isModalVisible = true
        }

        let expires = new Date()
        expires = expires.setHours(expires.getHours() + 24)

        localStorage.setItem('isModalVisible', expires)
      }
    }
  }

In your setDevHoursModal method, you're not always returning a value.在您的setDevHoursModal方法中,您并不总是返回一个值。 You could resolve this by just returning the result of the condition:您可以通过仅返回条件的结果来解决此问题:

setDevHoursModal(): boolean {
  if (localStorage) {
    let nextPopup = localStorage.getItem('isModalVisible');
    if (nextPopup > new Date()) {
      return (this.isModalVisible = true);  // let's be a little more explicit here
    }

    let expires = new Date();
    expires = expires.setHours(expires.getHours() + 24);

    localStorage.setItem('isModalVisible', expires);
    return false;
  }
  return true;
}

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