get_results("select * from table_name where id IN($array)") 但它假定 $array 为 "Array"

Question

I need to pass an array from get_results() to another query call to get_results()

My code is like this:

$getids = get_results("Select ID from table_name");

$getData = get_results("Select name from table where ID In($getids)");

But when I run this code Instead of $getids it is taking Array

Answer 1

Since $getids is an array, if you try to echo it as a string, you will get the word Array . Instead, you need to implode it to get a comma separated list of values ie

$getData = get_results("Select name from table where ID In(" . implode(',', $getids) . ")");

But you can get the data you want directly by using a JOIN in your query:

$getData = get_results("SELECT name 
                        FROM `table` t1
                        JOIN table_name t2 ON t2.ID = t1.ID");

Answer 2

$getids in an Array. You need to pass all ids as a comma-separated string like below:

$getids = get_results("Select ID from table_name");
$getids = implode( ',', $getids );
$getData = get_results("Select name from table where ID In($getids)");

Answer 3

$getids is a php array, for use in string variables you must use "implode" function:

//first check array is not empty
if(count($getids))
{
  //if your array is same as: $getids=array("ID"=>[1,2,3,4]) you must first convert it to flat array same as :$getids=[1,2,3,4] 
  // for example: $getids=$getids["ID"];
  $sql="Select name from table where ID In(".implode(",",$getids).")";
}