[英]mysql select join second row
task任务
task_id | content | date
-------------------------------
1 | task 1 | 2019-11-26
2 | task 2 | 2019-11-27
task_child task_child
id | task_id | type | date_task
--------------------------------
1 | 1 | A | 2019-11-26
2 | 1 | B | 2019-11-27
3 | 1 | A | 2019-11-28
4 | 1 | B | 2019-11-28
5 | 2 | A | 2019-11-26
6 | 2 | B | 2019-11-26
7 | 2 | C | 2019-11-28
Hi, I have two table as above, how do I join that table in order to get only 2nd row from each task_child?嗨,我有上面的两个表,我如何加入该表以便从每个 task_child 中只获取第二行?
The result should be like below:结果应如下所示:
task_id | content | type | date_task
------------------------------------
1 | task 1 | B | 2019-11-27
2 | task 2 | B | 2019-11-26
This should help:这应该有帮助:
SELECT
Task.task_id,
Task.content,
Task_Child.type,
Task.task_date
FROM
Task
INNER JOIN
Task_Child
ON
Task.task_id=Task_Child.task_id;
Hope this helps you.希望这对你有帮助。
If you are running MySQL 8.0, you can use row_number()
in a subquery to rank records in the child table within group having the same task_id
, and use it as a join filter:如果您运行的是 MySQL 8.0,则可以在子查询中使用row_number()
对组内具有相同task_id
的子表中的记录进行排名,并将其用作连接过滤器:
select t.task_id, t.content, c.type, c.date_task
from task t
inner join (
select c.*, row_number() over(partition by task_id order by date_task) rn
from task_child
) c on c.task_id = t.task_id and c.rn = 2
In earlier versions, this is a bit more complicated.在早期版本中,这有点复杂。 One solution would be to add a join condition with a subquery that ensures that there is just one record in the child table with the same task_id
and an earlier date_task
than the record currently being joined:一种解决方案是使用子查询添加连接条件,以确保子表中只有一个记录具有相同的task_id
和较早的date_task
比当前正在加入的记录:
select t.task_id, t.content, c.type, c.date_task
from task t
inner join task_child c
on c.task_id = t.task_id
and (
SELECT count(*)
from task_child c1
where c1.task_id = c.task_id and c1.date_task < c.date_task
) = 1
If you want the second status, you can use a correlated subquery:如果你想要第二个状态,你可以使用相关子查询:
select t.*,
(select tc.type
from task_child tc
where tc.task_id = t.task_id
order by tc.id
limit 1, 1
) as type
from task t;
Given that you want one column, this is probably the most efficient method, regardless of MySQL version.鉴于您想要一列,这可能是最有效的方法,无论 MySQL 版本如何。 For best performance, you want an index on task_child(task_id, id, type)
.为了获得最佳性能,您需要在task_child(task_id, id, type)
上有一个索引。
By using left join, you can get your required data. 通过使用左联接,您可以获得所需的数据。
SELECT t.task_id, t.content, tc.type, tc.task_date from task t LEFT JOIN task_child tc ON tc.task_id = t.id WHERE tc.id=2
Please refer for joins in more details 请参阅加入的详细信息
http://www.khankennels.com/blog/index.php/archives/2007/04/20/getting-joins/ http://www.khankennels.com/blog/index.php/archives/2007/04/20/getting-joins/
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