如何拆分列表中占据相同索引位置的元素？

Question

I am new to Python and can not seem to find a solution to what I am sure is a simple problem. I have a list of three elements but they occupy a single position. How can I split them up to store them in separate positions in a list?

Code:

li = [(2,3,6)]

Currently output

 li[0] = (2,3,6)

My desired output would be

li = [2,3,6]

So that li[0] = 2, li[1] = 3, li[2] = 6

Any help is much appreciated, thanks!

Answer 1

In your case, you can just convert the li[0] elements to list store them in separate variables. Or save it to the same one.

For ex:-

li = [(1,2,3)]

li = list(li[0])

print(li)

output

Output:
[1,2,3]

Answer 2

I have a list of three elements but they occupy a single position

Actually, here

li = [(2,3,6)]

li is not "a list of three elements", it's "a list of a single element", which single element is a tuple of three elements.

If you want to make a list of three elements from this, you have to

1/ extract the tuple from the list. It's the first element so it's at index zero:

elem = li[0]

2/ build a list from elem :

li = list(elem)

or, in a single statement:

li = list(li[0])